Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.
<h3>How can the duration of signal reception be found?</h3>
Radius of broadcast of the transmitter = 50 miles
Location of starting point = 56 miles north of the transmitter
Location of destination city = 58 miles east of the transmitter
Therefore we have;
Slope of the line joining the two cities
= 56 ÷ (-58) = -0.966
Which gives the equation of the line as follows;
y = -0.966•x + 56
The equation of the circle is;
1.933156•x^2 - 108.192•x + 636 = 0
Which gives;
Therefore;
When x = 6.67, we have;
- y = -0.966 × 6.67 + 56 = 49.56
When x = 49.29, we have;
- y = -0.966 × 49.29 + 56 = 8.4
The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;
l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>
- The length of the drive during which the signal is received is 59.24 miles
Learn more about the equation of a circle here:
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Answer:
The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).
Critical value t=1.318
Step-by-step explanation:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=0.165.
The sample size is N=25.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
The degrees of freedom for this sample size are:
The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).
<span>£19,500
10*37.5*52 =</span>£19,500
Make y the subject in both equations
For the second equation
The two equations are parallel because they have the same gradient or slope but different y intercepts.
This type of equations have no solution because they will never intersect.
The correct answer is C
