Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
7/3 3 I think that is the answer good luck
Answer:
A: 6, 12, 18, 24, 30
10, 20, 30, 40
B: 30
C: 5/6= 25/30 and 7/10= 21/30
D: 25/30>21/30 so 5/6>7/10
Answer:
(-2,1) (-3,0)
Step-by-step explanation:
It hits on the line
Answer B
There are 16 oz in a pound. 16(2)=32 and there are 4 oz leftover.
