Which value of y makes the inequality 3y^2 +2(y-5)>8 true?
1 answer:
Answer: D
Step-by-step explanation:
A) 3*0^2+2(0-5)>8
-10>8 -> not true
B) 3*(-1)^2+2(-1-5)>8
3*1+2*(-6)>8
3- 12>8
-9> 8 -> not true
C) 3*(-2)^2+2(-2-5)>8
3*4+2*(-7)>8
12-14>8
-2> 8 -> not true
D) ) 3*(-3)^2+2(-3-5)>8
3*9+2*(-8)>8
27-16>8
11> 8 -> true
You might be interested in
Answer:
C. Subtraction property of equality
Step-by-step explanation:
Y = 4 - x
3x + 4(4-x) = 14
3x + 16 -4x = 14
-x = -2
x = 2
y = 2
Answer:
it should be option 2 and 4
Step-by-step explanation:
Answer:
904.78 in I think but I'm not 100%
Answer:
y= 2/3x + 1.25
Step-by-step explanation:
I can't see the exact number but it's probably 1.25. Sorry if it's wrong :)
