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stealth61 [152]
3 years ago
6

Given:

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0
I hope this helps you

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5. The area of the trapezoid is 75 square inches. Find the height of the trapezoid. And it’s two bases are 10 and 15.
GaryK [48]
6

6
h/2(sum of bases) =75=area
h=3*2


Mark brainliest please
7 0
2 years ago
Which of the following is a composite number?<br><br> A)47<br><br> B)91<br><br> C)101<br><br> D)131
Varvara68 [4.7K]
91 = 7*13 is a composite number. It has factors other than itself and 1.
3 0
3 years ago
What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
IrinaK [193]
Given:

4log1/2^w (2log1/2^u-3log1/2^v)

Req'd:

Single logarithm = ?

Sol'n:

First remove the parenthesis,

4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)

Simplify each term,

Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:

 log 1/2 (w^4)  + 2 log 1/2 (u) - 3 log 1/2 (v) 
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)

We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):

Thus,

Log of 1/2 (w^4 u^2) - log of 1/2 (v^3) 

then use the quotient property of logarithms which is log of b (x)  - log of b (y) = log of b (x/y)

Therefore, 

log of 1/2 (w^4 u^2 / v^3)

and for the final step and answer, reorder or rearrange w^4 and u^2:

log of 1/2 (u^2 w^4 / v^3)  
8 0
3 years ago
Read 2 more answers
Write the equation of a line, in slope-intercept form<br> (1,1);(-2,-11)<br> Y =
bonufazy [111]

Answer:

Y =4X  -3

Step-by-step explanation:

x1 y1  x2 y2

1 1  -2 -11

   

(Y2-Y1) (-11)-(1)=   -12  ΔY -12

(X2-X1) (-2)-(1)=    -3  ΔX -3

   

slope= 4          

B= -3          

   

Y =4X  -3    

6 0
3 years ago
Read 2 more answers
Use the distribute property to find two expressions that are equivalent to 7(3x-4)
timama [110]

84 Is the answer thank me later god bless you

8 0
2 years ago
Read 2 more answers
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