Answer:
![P = 1.090\,N](https://tex.z-dn.net/?f=P%20%3D%201.090%5C%2CN)
Explanation:
The constant speed means that ball is not experimenting acceleration. This elements is modelled by using the following equation of equilibrium:
![\Sigma F = P - W + F_{D}](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%20P%20-%20W%20%2B%20F_%7BD%7D)
![\Sigma F = P - \rho \cdot V \cdot g + c\cdot v = 0](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%20P%20-%20%5Crho%20%5Ccdot%20V%20%5Ccdot%20g%20%2B%20c%5Ccdot%20v%20%3D%200)
Now, the exerted force is:
![P = \rho \cdot V \cdot g - c\cdot v](https://tex.z-dn.net/?f=P%20%3D%20%5Crho%20%5Ccdot%20V%20%5Ccdot%20g%20-%20c%5Ccdot%20v)
The volume of a sphere is:
![V = \frac{4\cdot \pi}{3}\cdot R^{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%5Ccdot%20%5Cpi%7D%7B3%7D%5Ccdot%20R%5E%7B3%7D)
![V = \frac{4\cdot \pi}{3}\cdot (0.014\,m)^{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%5Ccdot%20%5Cpi%7D%7B3%7D%5Ccdot%20%280.014%5C%2Cm%29%5E%7B3%7D)
![V = 1.149\times 10^{-5}\,m^{3}](https://tex.z-dn.net/?f=V%20%3D%201.149%5Ctimes%2010%5E%7B-5%7D%5C%2Cm%5E%7B3%7D)
Lastly, the force is calculated:
![P = (8910\,\frac{kg}{m^{3}} )\cdot (1.149\cdot 10^{-5}\,m^{3})\cdot (9.81\,\frac{m}{s^{2}} )+(0.950\,\frac{kg}{s})\cdot (0.09\,\frac{m}{s} )](https://tex.z-dn.net/?f=P%20%3D%20%288910%5C%2C%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%7D%20%29%5Ccdot%20%281.149%5Ccdot%2010%5E%7B-5%7D%5C%2Cm%5E%7B3%7D%29%5Ccdot%20%289.81%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%2B%280.950%5C%2C%5Cfrac%7Bkg%7D%7Bs%7D%29%5Ccdot%20%280.09%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29)
![P = 1.090\,N](https://tex.z-dn.net/?f=P%20%3D%201.090%5C%2CN)
Answer:
it is ---D because you can't measure gas and it's mass
HOPE THIS HELPS
Given:
F_gravity = 10 N
F_tension = 25 N
Let's find the net centripetal force exterted on the ball.
Apply the formula:
![\sum ^{}_{}F_{\text{net}}=F_1+F_2=F_{centripetal}](https://tex.z-dn.net/?f=%5Csum%20%5E%7B%7D_%7B%7DF_%7B%5Ctext%7Bnet%7D%7D%3DF_1%2BF_2%3DF_%7Bcentripetal%7D)
From the given figure, the force acting towards the circular path will be positive, while the force which points directly away from the center is negative.
Hence, the tensional force is positive while the gravitational force is negative.
Thus, we have:
![F_{\text{net}}=F_{\text{centripetal}}=F_{tension}-F_{gravity}=25N-10N=15N](https://tex.z-dn.net/?f=F_%7B%5Ctext%7Bnet%7D%7D%3DF_%7B%5Ctext%7Bcentripetal%7D%7D%3DF_%7Btension%7D-F_%7Bgravity%7D%3D25N-10N%3D15N)
Therefore, the net centripetal force exterted on the ball is 15 N.
ANSWER:
15 N
Best Answer: <span>There is little or no surplus so the social inequalities are not significant and economic interaction takes place within egalitarian frame-work.
Brainliest would be awesome</span>
1 metre per second = 2.237 miles per hour
so 83 m/sec = 185.666 miles per hour !! ...answer !!