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zhannawk [14.2K]
3 years ago
10

What is the entropy of a closed system in which 28 distinguishable grains of sand are distributed among 1000 distinguishable equ

al-sized compartments?
Physics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

193.4 J/K

Explanation:

For a closed system, the entropy is given as the natural logarithm of microstates.

The number of particles ( grains of sand ) N = 28

The number of boxes ( compartments ) M = 1000

Entropy is the logarithm of number of microstates

S=ln \psi

But the number of microstates is given by

\psi=M^{N} hence S=ln M^{N}=\ln (1000^{28})= \boxed{193.4 J/K}

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