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Mashutka [201]
3 years ago
15

Which property is shown? (mn)^5=m^5n^5

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0
A.) Product of powers
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Your school’s band decides to sell cookie dough kits to raise money for a spring field trip. There is a Family Times Cookie Doug
nikitadnepr [17]

Answer:

 

Step-by-step explanation:

let the Cookie Dough kit be x

and  Baker’s Delight kit be y

cost of Cookie Dough kit= $7

cost of  Baker’s Delight= $15

so

x+y=220------------1

7x+15y=2100------2

solve for x and y we have

multiply eqn 1 by 7 and subtract

  7x+7y=1540---------3

-  7x+15y=2100-------2

  0x-8y=-560

8y=560

divide both sides by 8 we have

y=560/8

y=70

put y=70 in eqn 1 we have

x+70=220

x=220-70

x=150

x=220-70

x=150

A. How many of each type of kit should your band purchase to raise the most money

Cookie Dough kit= 150

Baker’s Delight= 70

B. What is the most money that your band can raise?

Cookie Dough kit profit= selling price-cost price= 12-7= $5

Baker’s Delight profit= selling price-cost price= 25-15= $10

Amount made for Cookie Dough = 150*5=$750

Amount made for Baker’s Delight = 70*10=$700

total= 750+700= $1450

3 0
3 years ago
F(x) = ( - 3x² + 2 – 2)e". Find f'(x) and f''(x).<br> f'(2) =<br> f''(c)<br> =
prisoha [69]

Answer:

-3x²-5xeˣ-eˣ

-3eˣx²-11eˣx-6eˣ

Step-by-step explanation:

I'm going to go by the picture and not what you wrote in your title.

To find the derivative of this we have to apply the product rule

(a*b)'=

a'*b+a*b'

We plug in our numbers and get

(-3x²+x-2)'*eˣ+(-3x²+x-2)*eˣ'

Now we can evaluate the derivatives and simplify

(-3x²+x-2)'= -6x+1

eˣ'=eˣ

which means we have

(-6x+1)*eˣ+(-3x²+x-2)*eˣ

Simplify

-6xeˣ+eˣ-3x²eˣ+xeˣ-2eˣ

Combine like terms

-3x²eˣ-5xeˣ-eˣ

Now we just need to find the derivative of this

We can apply the same product rule as we did before

(-3x²eˣ)'

Let's start by factoring out the -3 to get

-3(x²eˣ)'

which is equal to

-3(x²eˣ'+x²'eˣ)

Compute this and get

-3(x²eˣ+2xeˣ)= -3x²eˣ-6xeˣ

Now let's find the derivative of the second part

(-5xeˣ)'

-5(x'eˣ+xeˣ')

-5(eˣ+xeˣ)

-5eˣ-5xeˣ

Which means we have

(-3x²eˣ-6xeˣ)+(-5eˣ-5xeˣ)-eˣ

Combine like terms and get

-3eˣx²-11eˣx-6eˣ

3 0
4 years ago
Suppose customers in a hardware store are willing to buy N(p) boxes of nails at p dollars per box, as given by the following fun
Viktor [21]

Answer:

(a) - 25 boxes per dollar

(b) - 20 boxes per dollar

Step-by-step explanation:

Given that,

Consumer's willing to buy boxes of nails at p dollars per box:

N(p) = 80 - 5p^{2}

(a) Change in price from $2 to $3.

N(2) = 80 - 5(2)^{2}

       = 80 - 20

       = 60

N(3) = 80 - 5(3)^{2}

       = 80 - 45

       = 35

Therefore, the average rate of change of demand is

= [N(3) - N(2)] ÷ (3 - 2)

= 35 - 60

= - 25 boxes per dollar.

(b) N(p) = 80 - 5p^{2}

Now, differentiating the above function with respect to p,

N'(p) = -10p

Therefore, the instantaneous rate of change of demand when the price is $2 is calculated as follows:

N'(p) = -10p

N'(2) = -10 × 2

        = -20 boxes per dollar

7 0
3 years ago
Addie bought lunch to go from a sandwich shop. She spent $12.00 for a $10.00 meal. What percent was the tip?
horsena [70]

Answer:

She gave a $2.00 tip witch would be %20 of her meal cost.

Step-by-step explanation:

    </3 PureBeauty

4 0
3 years ago
Read 2 more answers
A bullet with a mass of 0.005 kg is shot at a speed of 40
marin [14]

Answer:

combined velocity of the system = 0.033 m/s.

Step-by-step explanation:

taking the bullet and block as single system since there is no external force involved momentum is conserved .

initial momentum of the bullet = mv

where m is the mass of bullet and v is velocity of bullet.

and initial momentum of block = 0 since its velocity is 0.

therefore initial momentum of the system = mv

                                                                      = 0.005×40

                                                                      = 0.2

when the bullet stick of together with the block let the combined velocity of the system be V

therefore applying conservation of momentum

mv = (M+m)V

0.2=(6+0.005)V

therefore V = 0.033 m/s

7 0
3 years ago
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