A. 7+4=11. That’s the answer to the hypotenuse.
<span>A polynomial with the given zeros can be represented as
f(x) = (x-1)(x-2)(x+2)(x+3).
Note that if you set f(x) = 0, then 1,2,-2, and -3 certainly are the solutions. From here, we simply multiply/expand out the polynomial. We can do this in a variety of ways, one of which is taking the left two and right two products separately. We have
(x-1)(x-2) = x^2 - 3x + 2
and
(x+2)(x+3) = x^2 + 5x + 6.
This gives that
f(x) = (x^2 - 3x + 2) (x^2 + 5x + 6).
Expanding this expression out then gives us our answer as
f(x) = x^4 + 2x^3 - 7x^2 - 8x + 12
or answer choice B.</span>
Answer:
6
Step-by-step explanation:
Given mixed operations there is a particular order that must be followed.
Using the order set out in the acronym PEMDAS
P - Parenthesis ( brackets ), E- Exponents ( powers ), M - Multiplication, D - Division, A- Addition, S - Subtraction
8 + 24 ÷ (2 × 6) - 4
= 8 + 24 ÷ 12 - 4 ← parenthesis
= 8 + 2 - 4 ← division
= 10 - 4 ← addition
= 6 ← subtraction
Answer:
g(x) = x^2/16
Step-by-step explanation:
To stretch a function horizontally by a factor of k, replace x with x/k.
You want a stretch factor of 4, so your function is ...
g(x) = f(x/4) = (x/4)^2
g(x) = x^2/16
__
The attached graph shows the horizontal stretch.
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)
Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141
(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71
(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000
</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x
taking "ln" on both sides:
ln(4.797) = ln(1.19)^x
ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)
