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Thepotemich [5.8K]
3 years ago
8

What is this |7| = suppose to mean

Mathematics
2 answers:
romanna [79]3 years ago
4 0

Answer:

7

Step-by-step explanation:

|7|

The bars on the outside means absolute value

It means calculate what is on the inside and then take the positive value

The positive value of 7 is 7

If we had | 3-7|  We would find 3-7 = -4  then take the positive value = 4

Anestetic [448]3 years ago
3 0

Answer:

It is meaning basically the absolute value.

Step-by-step explanation:

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It'll be the third one because he stops to shop for a bit, then goes straight home.
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Construct a rectangle with sides 6cm and 4cm.​
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On a piece of paper, use a protractor to construct △ABC with m∠A=30° , m∠B=60° , and m∠C=90° .
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It's a right triangle.

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3 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
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Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

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3 years ago
The difference of two numbers is 34 and their sum is 338
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X-y=34
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We can use elimination in this problem.

2x=372
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