All categories

3 years ago

What is this |7| = suppose to mean

Mathematics

2 answers:

romanna [79]3 years ago

4 0

Answer:

Step-by-step explanation:

|7|

The bars on the outside means absolute value

It means calculate what is on the inside and then take the positive value

The positive value of 7 is 7

If we had | 3-7| We would find 3-7 = -4 then take the positive value = 4

Anestetic [448]3 years ago

3 0

Answer:

It is meaning basically the absolute value.

Step-by-step explanation:

You might be interested in

Does anyone know how to solve this?

g100num [7]

Yes, 16.3 is y maybe but or else I need to use a protractor I believe

4 0

3 years ago

The line segment joining the points a (3,2) and b (5,1) is divided at the point p in the ratio 1:2 and p lies on the line 2x-18y

kumpel [21]

your answer would be 2x-18y+k=0

8 0

3 years ago

Suppose you estimated square root of 12 by averaging a square like rectngle.What would be a reasonable estimation?

sesenic [268]

Answer:

3.5.

Step-by-step explanation:

3^2 = 9

and 4^2 = 16 so the square root is between 3 and 4.

Take a rectangle 3.4 by 3.6:

the area = 3.4 * 3.6 = 12.24 so an estimate of the square root could be 3.5.

3.5 * 3.5 = 12.25.

5 0

2 years ago

The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall

Morgarella [4.7K]

Answer:

$(y-1)=\frac{3}{2}(x+3)$

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

$(y-1)=\frac{3}{2}(x+3)$

3 0

3 years ago

The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after

Olenka [21]

To solve this we are going to use the half life equation $N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }$
Where:
$N_{0}$ is the initial sample
$t$ is the time in years
$t_{1/2}$ is the half life of the substance
$N(t)$ is the remainder quantity after $t$ years

From the problem we know that:
$N_{0} =100$
$t=200$
$t_{1/2} =1600$

Lets replace those values in our equation to find $N(t)$ :
$N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }$
$N(200)=100e^{( \frac{-138.6}{1600} )}$
$N(200)=100e^{-0.086625}$
$N(200)=91.7$

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0

3 years ago