Apply the Mean Value Theorem and find a value of c in the interval
2 answers:
If f(x) is continuous on [a,b] and differtiable on the open interval (a,b) then c exists such that f’(c) = f(b) - f(a) / b-a.
Using the given function f(x) = sqrt (x)
And the given interval [4,9]
F(c) = sqrt(9) - sqrt (4) / 9-4
= 3-2 / 5
= 1/5
C = 1/5
Answer:
c = 1444/225
Step-by-step explanation:
1/(9-4) × integral sqrt(x)
1/5 [⅔ × x^(3/2)]
Apply limits
(2/15)[9^(3/2) - 4^(3/2)]
(2/15)(27 - 8)
(2/15)(19)
38/15
38/15 = sqrt(c)
c = 1444/225
Or, 6.41777777778
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Multiply each number by 10. The constant of proportionality is 10. You can do it!!
Answer:
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Step-by-step explanation:
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Its D. because 6 = 600 so 2 tens + 600 = 620 so 15 plus all of the above is 645 :D hope this helped