1. (3 + xz)(–3 + xz)
2. (y² – xy)(y² + xy)
3. (64y2 + x2)(–x2 + 64y2)
Explanation
The difference of 2 squares is in the form (a+b)(a-c).
(3 + xz)(–3 + xz) = (3 + xz)(xz -3)
= (xz + 3)(xz - 3)
= x²y²-3xy+3xy-9
=x²y² - 3²
(y² – xy)(y² + xy) = y⁴+xy³-xy³-x²y²
= y⁴ - x²y²
(64y2 + x2)(–x2 + 64y2)= (64y²+x²)(64y²-x²)
= 4096y⁴-64y²x²+64y²x²-x⁴
= 4096y⁴ - x⁴
Expand the brackets first
5(wx-v) = 9(x + v)
5wx - 5v = 9x + 9v
Get all x's on one side and everything on on the other side
9x - 5wx = 9v + 5v
factorise out the x
x(9-5w) = 14v
then divide by 9-5w
x = 14v/(9-5w)
So we know that:
3(-8 + 4v) = 8v
To find v, first simplify the left hand side:
-24 + 12v = 8v
Then group the "v's" over to the right:
-24 = -4v
-6 = -v
So v = 6
Hope this helped
Step-by-step explanation:
first, add the whole numbers
6 + 7 = 13
then the fractions
3/8 + 5/6
we need to get common denominators
do you know how to do that
