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yKpoI14uk [10]
3 years ago
5

What is the total weight, in pounds, of 100 sharks that each weigh 5.015× 10 (to the 3rd power) pounds

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

12612837.8375

Step-by-step explanation:

first you have to multiply 5.015 x 10 and you get 50.15 the put that to the power of 3 and then multiply the total by 100.

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What is negative thirty divided by three
Phoenix [80]

Answer:

The answer is -10

Step-by-step explanation:

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Someone please help me on this question ?:)
katrin2010 [14]

Answer: The TV is 48 inches wide.

Step-by-step explanation: To find the solution to this equation we must use the Pythagorean theorem. The Py. Theo. is basically the formula :

a^2 + b^2 = c^2    You say this as "A squared plus b squared equals c squared"

To use this formula you must plug in the given values of a and b, to find c. A and b represent the two bases of the triangle, while c is the hypotenuse. In this equation we already have the value of c and a. We need to find b, but in order to do that we use a different formula. We use : c^2 - a^2 = b^2

See :

52^2 - 20^2 = b^2       *The ^2 means "to the power of" aka an exponent*

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48 = b    

*Another way to solve this equation is to memorize all the Pythagorean Triples. With that knowledge, you wont even need to use the formula because you will already know all three values. I hope this helped you understand :)



3 0
3 years ago
Giving 100 points.
Nitella [24]

Answer:

1.   <u>Cost per customer</u>:  10 + x

     <u>Average number of customers</u>:  16 - 2x

\textsf{2.} \quad  -2x^2-4x+160\geq 130

3.    $10, $11, $12 and $13

Step-by-step explanation:

<u>Given information</u>:

  • $10 = cost of buffet per customer
  • 16 customers choose the buffet per hour
  • Every $1 increase in the cost of the buffet = loss of 2 customers per hour
  • $130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

<u>Part 1</u>

<u></u>

<u>Cost per customer</u>:  10 + x

<u>Average number of customers</u>:  16 - 2x

<u>Part 2</u>

The cost per customer multiplied by the number of customers needs to be <u>at least</u> $130.  Therefore, we can use the expressions found in part 1 to write the <u>inequality</u>:

(10 + x)(16 - 2x)\geq  130

\implies 160-20x+16x-2x^2\geq 130

\implies -2x^2-4x+160\geq 130

<u>Part 3</u>

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

\implies -2x^2-4x+160\geq 130

\implies -2x^2-4x+30\geq 0

\implies -2(x^2+2x-15)\geq 0

\implies x^2+2x-15\leq  0

\implies (x-3)(x+5)\leq  0

Find the roots by equating to zero:

\implies (x-3)(x+5)=0

x-3=0 \implies x=3

x+5=0 \implies x=-5

Therefore, the roots are x = 3 and x = -5.

<u>Test the roots</u> by choosing a value between the roots and substituting it into the original inequality:

\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144

As 144 ≥ 130, the <u>solution</u> to the inequality is <u>between the roots</u>:  

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.  

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an <em>increase </em>in cost.  It does not confirm that if the cost is reduced (less than $10) the number of customers <em>increases </em>per hour.]

<u>Cost per customer</u>:  

x =0 \implies 10 + 0=\$10

x=3 \implies 10+3=\$13

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0
2 years ago
Is line 1 (1,5) (3,-2) and like 2 (-3,2) (4,0) perpendicular of parallel?
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So remember that <u>perpendicular lines have slopes that are negative reciprocals to each other</u> and <u>parallel lines have the same slope.</u> To find out if they are either parallel or perpendicular, plug the pair of points into the slope formula to find their slopes:

\textsf{Line 1}\\\\\frac{5-(-2)}{1-3}=-\frac{7}{2}\\\\\textsf{Line 2}\\\\\frac{0-2}{4-(-3)}=-\frac{2}{7}

Since these slopes aren't the same nor are they negative reciprocals to each other, <u>the lines are neither parallel nor perpendicular.</u>

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3 years ago
Consider the following polynomials (x+3)(x+9)(x-6) = 0.Which of the following are zeros of the function?
mote1985 [20]
The solutions are:
-9, -3, 6, 
3 0
3 years ago
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