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3 years ago

13

Factories and other industrial users account for about 23/50 of the total water usage in the United States. Which of the followi

ng show that amount as a percent and decimal.

1 answer:

mihalych1998 [28]3 years ago

6 0

23 / 50 = 0.46

0.46 converted to a percent is 46%

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A square has an area of 4 square centimeters. What is the length of one side, in centimeters?

Lunna [17]

Answer:

2 cm

Step-by-step explanation:

$\sqrt{4 cm^{2}} =2 cm$

7 0

3 years ago

The student body of 115 students want to elect a president and a vice president. How many different ways can they do that

Hitman42 [59]

The different ways that the students can elect a president and a vice president will be 13110.

<h3>What is probability?</h3>

The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,

Given data;

Total no of students = 115

The total number of ways to elect a president = 115

If one person is elected as the president the total number of ways to elect a president = 114

The different ways that the students can elect a president and a vice president are found as;

⇒ 115 ways × 114 ways

⇒ 13110 ways

Hence the different ways that the students can elect a president and a vice president will be 13110.

To learn more about probability, refer to the link;

brainly.com/question/11234923

#SPJ1

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2 years ago

Vickie made a recipe for 144 fluid ounces of scented candle wax. How many 1-cup candle molds can she fill with the recipe

Gre4nikov [31]

there are 0.125 cups inside 1 fluid ounces

144 / 0.125 = 1152 (divide because you are trying to figure out how many of the volumes of the mold can fit inside the 144 fluid ounces

You can fill 1152 molds with 144 fluid ounces

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4 years ago

SCORPION-xisa [38]

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Given
A midpoint splits a segment into two congruent parts
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8 0

2 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago