All categories

3 years ago

Question 3

Mathematics

1 answer:

Gala2k [10]3 years ago

4 0

Answer:

✨✨✨✨✨✨✨✨✨✨✨✨✨

Step-by-step explanation:

You might be interested in

What’s the volume of a cylinder with a base of 25 and height of 6

Anastasy [175]

Approximately 2945.24 units

4 0

2 years ago

Read 2 more answers

How many times greater is the population of Illinois than the population of Alaska?

Jet001 [13]

Answer:

17 times

Step-by-step explanation:

IIIinois : 12670000

Alaska : 731545

12670000/731545=17.31

5 0

3 years ago

Read 2 more answers

What is the following simplified product? Assume x greater-than-or-equal-to 0 2 StartRoot 8 x cubed EndRoot (3 StartRoot 10 x Su

RideAnS [48]

This is the simplest form $4\sqrt{5}x^3(6\sqrt{x} -\sqrt{2})$ .

<h2>Exponent</h2>

Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.

<h3>Simplification</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

$\rm 2\sqrt{8x^3} * (3\sqrt{10x^4} - x\sqrt{5x^2} )$ is an expression.

<h3>How to make it simple?</h3>

$\rm 2\sqrt{8x^3} * (3\sqrt{10x^4} - x\sqrt{5x^2} )$

On simplifying, we have

$\rm 4\sqrt{2} (x)^{\frac{3}{2}} * ( 3\sqrt{10} x^2 - \sqrt{5} x^{\frac{3}{2}})\\\\24\sqrt{5} x^{\frac{7}{2}} - 4\sqrt{10}x^3\\\\4\sqrt{5}x^3(6\sqrt{x} -\sqrt{2} )\\$

This is the simplest form $4\sqrt{5}x^3(6\sqrt{x} -\sqrt{2})$ .

More about the exponent link is given below.

brainly.com/question/5497425

7 0

2 years ago

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

<u>Calculus</u>

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 6x + 19

Interval [12, 15]

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$