(8u³ + 8u² + 6) + (4u³<span> - 6u + 3) =
</span>8u³ + 8u² + 6 + 4u³ - 6u + 3 =
12u³ + 8u² - 6u + 9
Answer:
Least to greatest
Step-by-step explanation:
912.202
912.21
913.601
913.61
Add zero's next time, (to 912.21 and 913.61
. It could help.)
We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
4398200 because get rid of the ones after 200