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Romashka-Z-Leto [24]
4 years ago
7

Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20? (1 point)

x greater than or equal to 9 9 less than or equal to x A number line with a closed circle on 9 and shading to the left A number line with a closed circle on 9 and shading to the right
Mathematics
1 answer:
madreJ [45]4 years ago
5 0
2x+2≥20
2x≥18
x≥9

closed circle on 9 because of the = in ≥ and the line going off to the right

please ask if you need more information or clarification
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How many tree's are 10.5 tree's?
sladkih [1.3K]

Answer:

11

Step-by-step explanation:

you have to round the decimal 5 to the top to get a whole number which is 11 , and I'm guessing 10 grown trees and a little one

6 0
4 years ago
James says,
Dima020 [189]

-3^3 = -27

Step-by-step explanation:

Thats because -3^3 is (-3×3×3) not (-3×-3×-3) which we are multiplying a the constant not the the powers

6 0
3 years ago
Read 2 more answers
Find the missing value. Show your work. please
Sophie [7]
#1
sin(51^o)= \frac{y}{12} \ \ \to \ \ y=12*sin(51^o)=12* 0.7771 \approx 9.33

#2
\theta=arccos( \frac{5^2+13^2-12^2}{2*5*13}) = arccos( \frac{25+169-144}{130})=arccos( \frac{50 }{130})= \\ \\ arccos(0.3846) \approx67.4^o

#3
tan(13^o)= \frac{x}{24} \ \ \to \ \ x=24*tan(13^o)=24* 0.2309 \approx 5.54

#4
sin(20^o)= \frac{10}{x} \ \ \to \ \ x= \frac{10}{sin(20^o)} = \frac{10}{0.342}  \approx 29.24
5 0
4 years ago
Write an equation of the line that passes through(2,7) and (0,-5)
SVETLANKA909090 [29]

Answer:

-6x + y = -5\:or\:y = 6x - 5

Step-by-step explanation:

First, find the <em>rate of </em><em>change</em><em> </em>[<em>slope</em>]:

\frac{-y_1 + y_2}{-x_1 + x_2} = m

\frac{-7 - 5}{-2 ± 0} = \frac{-12}{-2} = 6

Then plug these coordinates into the Slope-Intercept Formula instead of the <em>Point-Slope</em><em> </em><em>Formula</em><em> </em>because you get it done much swiftly. In this case, we have a y-intercept of [0, -5], so this is a giveaway. It does not matter which ordered pair you choose:

-5 = b \\ \\ y = 6x - 5

If you want it in <em>Standard</em><em> </em><em>Form</em>:

y = 6x - 5

- 6x - 6x

_________

-6x + y = -5

_______________________________________________

7 = 6[2] + b

12

-5 = b \\ \\ y = 6x - 5

y = 6x - 5

- 6x - 6x

_________

-6x + y = -5

** You see? I told you it did not matter which ordered pair you choose because you will always get the exact same result.

I am joyous to assist you anytime.

5 0
4 years ago
Which of the following integrals represents the area of the region bounded by x = 0, x = 1 and the functions f(x) = -2x4 and g(x
leva [86]

Answer:

C. \int\limits^0_1 {-2x^4-x^2} \, dx is correct

Step-by-step explanation:

We are given that,

The region bounded by x= 0, x=1, f(x)= -2x^4, g(x)=x^2 is given in the figure below.

Now, as we have,

Area of the bounded region = \int\limits^a_b {f(x)-g(x)} \, dx,

where f(x) represents the upper curve and f(x) represents the lower curve in the bounded region.

So, as we see that,

The upper curve in the given region is f(x)= -2x^4 and the lower curve is g(x)=x^2.

Thus, the integral showing the area of the given region is,

\int\limits^0_1 {-2x^4-x^2} \, dx

Hence, option C is correct.

6 0
3 years ago
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