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Scorpion4ik [409]
2 years ago
5

En un distrito, hay una calle peatonal. El municipio decidió colocar faroles, bancas y sembrar árboles para mejorar el ornamento

. Los faroles serán colocados cada 30 metros, las bancas cada 20 metros y los árboles serán sembrados cada 50 metros. ¿Cada cuántos metros volverán a coincidir un farol, una banca y un árbol?
Mathematics
1 answer:
olga_2 [115]2 years ago
6 0

Answer:

El lugar donde la linterna, los bancos y los árboles se encuentran nuevamente está a 300 metros del punto de inicio.

Step-by-step explanation:

Los parámetros dados son;

El espacio entre las linternas = 30 metros.

El espacio entre los bancos = 20 metros.

El espacio entre los árboles = 50 metros.

Por lo tanto, tenemos, la ubicación donde la linterna, los bancos y los árboles se encuentran nuevamente, está dada por el mínimo común múltiplo de cada una de sus distancias de separación individuales como sigue;

      2   divide   30   20   50 {}  

{}      <u>5  divide    15    10    25</u>

{}                           3      2    5

El LCM = 2 × 5 × 3 × 2 × 5 = 300

El lugar donde la linterna, los bancos y los árboles se vuelven a encontrar está a 300 metros del punto de inicio.

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Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percen
KiRa [710]

Answer:

Step-by-step explanation:

Both cars, X and Y travelled 80 miles each.

Speed = distance/time

If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is

80/2 = 40 mph

If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is

40 + 0.5 × 40 = 60 mph

Time = distance/speed

Therefore, time taken by car Y to travel 80 miles is

80/60 = 1.33 hours

7 0
3 years ago
Please help me! I think this 20 character thing is unnecessary when you have an attachment
PIT_PIT [208]

Answer:

B

Step-by-step explanation:

Also the answer must be under 9 so that rules out option D

Because We know CE = 2 and AD is visibly larger than CE, 6We can rule out option A

And that brings us down to B and C

CB is equal to 6, And I'm no genius, but I'm pretty sure AD is DEFINATLY not equal to 6.

so the answer is B

8 0
3 years ago
Somebody please help!!!<br> (Dont judge me I forgot)
ch4aika [34]

Answer:

16. 200+3

17. 30+4+0.1+0.02+0.007

18. 200+70+6+0.1+0.03

19. 30000000+4000000+100000+20000+3000+6

Step-by-step explanation:

4 0
3 years ago
Each observation indicates the primary position played by the Hall of Famers: pitcher (P), catcher (H), 1st base (1), 2nd base (
gregori [183]

Answer:

a. See below for the Frequency and Relative frequency Table.

b. Pitcher (P) is the position provides the most Hall of Famers.

c. 3rd base (3) is the position that provides the fewest Hall of Famers.

d. R is the outfield position that provides the most Hall of Famers.

e. Th number of Hall of Famers of Infielders which is 16 is less than the 18 Hall of Famers of those of outfielders.

Step-by-step explanation:

Note: This question not complete. The complete question is therefore provided before answering the question as follows:

Data for a sample of 55 members of the Baseball Hall of Fame in Cooperstown, New York, are shown here. Each observation indicates the primary position played by the Hall of Famers: pitcher (P), catcher (H), 1st base (1), 2nd base (2), 3rd base (3), shortstop (S), left field (L), center field (C), and right field (R).

L P C H 2 P R 1 S S 1 L P R P

P P P R C S L R P C C P P R P

2 3 P H L P 1 C P P P S 1 L R

R 1 2 H S 3 H 2 L P

a. Use frequency and relative frequency distributions to summarize the data.

b. What position provides the most Hall of Famers?

c. What position provides the fewest Hall of Famers?

d. What outfield position (L, C, or R) provides the most Hall of Famers?

e. Compare infielders (1, 2, 3, and S) to outfielders (L, C, and R).

The explanation of the answers is now provided as follows:

a. Use frequency and relative frequency distributions to summarize the data.

The frequency is the number of times a position occurs in the sample, while the relative frequency is calculated as the frequency of each position divided by the sample size multiplied by 100.

Therefore, we have:

<u>Frequency and Relative frequency Table  </u>

<u>Position</u>           <u>Frequency </u>         <u> Relative frequency (%) </u>

P                               17                             30.91%

H                               4                               7.27%

1                                5                               9.09%

2                               4                               7.27%

3                               2                               3.64%

S                               5                               9.09%

L                               6                               10.91%

C                              5                                 9.09%

R                        <u>      7     </u>                          <u>  12.73% </u>

Total                  <u>     55   </u>                          <u>   100%   </u>

b. What position provides the most Hall of Famers?

As it can be seen from the frequency table in part a, Pitcher (P) has the highest frequency which is 17. Therefore, Pitcher (P) is the position provides the most Hall of Famers.

c. What position provides the fewest Hall of Famers?

As it can be seen from the frequency table in part a, 3rd base (3) has the lowest frequency which is 2. Therefore, 3rd base (3) is the position that provides the fewest Hall of Famers.

d. What outfield position (L, C, or R) provides the most Hall of Famers?

As it can be seen from the frequency table in part a, we have:

Frequency of L = 6

Frequency of C = 5

Frequency of R = 7

Since R has the highest frequency which is 7 among the outfield position (L, C, or R), it implies that R is the outfield position that provides the most Hall of Famers.

e. Compare infielders (1, 2, 3, and S) to outfielders (L, C, and R).

Total frequency of infielders = Frequency of 1 + Frequency of 2 + Frequency of 3 + Frequency of S = 5 + 4 + 2 + 5 = 16

Total frequency of outfielders = Frequency of L + Frequency of C + Frequency of R = 6 + 5 + 7 = 18

The calculated total frequencies above imply that number of Hall of Famers of Infielders which is 16 is less than the 18 Hall of Famers of those of outfielders.

5 0
3 years ago
Martha took her family out to dinner. Their total bill was $32.58. She decided to leave their server a 20% tip. How much did Mar
MrMuchimi
$32.58 x 20% (0.2) = 6.156
Just round it and you get $6.16
4 0
3 years ago
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