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4 years ago

Two straight lines VZ and YW intersect at X

Mathematics

1 answer:

Alexeev081 [22]4 years ago

5 0

Answer:

∠WVX = 35°

Step-by-step explanation:

Look at the rough draw.

As you can see,

VW ║ YZ

So ∠XWV is congruent to ∠XYZ through alternate interior angle.

We can solve ∠WVX by considering the two other angles, 88° and 57°.

Total angle of a triangle is 180°.

So,

? + 88 + 57 = 180

? + 145 = 180

? = 180 - 145

? = 35°

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Hey $149 stereo is on sale for $125 what percent discount was given?

Inessa [10]

Answer:

16.10738255 % discount

Step-by-step explanation:

6 0

4 years ago

5. In the diagram shown below, BC is drawn tangent

Tatiana [17]

9514 1404 393

Answer:

(2) 72°

Step-by-step explanation:

In this geometry, the angle at the tangent is half the measure of the intercepted arc.

∠CBD = (arc BD)/2 = 144°/2

∠CBD = 72°

<em>Additional comment</em>

Consider a point X anywhere on long arc BD. The inscribed angle at X will have half the measure of short arc BD, so will be 144°/2 = 72°. This is true regardless of the position of X on long arc BD. Now, consider that X might be arbitrarily close to point B. The angle at X is still 72°.

As X approaches B, the chord XB approaches a tangent to the circle at B. Effectively, this tangent geometry is a limiting case of inscribed angle geometry.

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3 years ago

A pair of snow boots at an equipment store in Big Bear that originally cost $60 is on sale for 40% off. Then, you have a coupon

Liono4ka [1.6K]

Answer:

30 dollars i think

Step-by-step explanation:

8 0

4 years ago

How many bitstrings of length 10 contain three consecutive 0’s or 4 consecutive 1’s? How many bitstrings of length 10 contain tw

Yuki888 [10]

Answer:

147 bitstrings.

Step-by-step explanation:

To start with, we will compute the number of bit strings that has 3 consecutive 0's.

For each of the consecutive 0's, they can start at either 1st, 2nd, 3rd or 4th positions (because there are eight positions)

If we begin from the 1st position, there will be strings in the form of 000xxxxx

The other positions can be anything, count= 25 =32.

If we begin from the 2nd position, there will be strings in the form of 1000xxxx.

Note that the 1st position must contain 1, otherwise there will be more than one count strings.

The remaining 4 positions can be anything, count= 24 = 16.

If we begin from the 3rd position, there will be strings in the form of x1000xxx.

Note that the 2nd position must contain 1, or there will be more than one count strings as in the first scenario.

The remaining 4 positions can be anything, count= 24=16.

If we begin from the 4th, 5th, or 6th position, it would be the same analysis.

Therefore,

total count= 32 + 16 + 16 + 16 + 16 +16 = 112.

From the analysis done so far, we have double counted these 5 strings: 00010000, 00010001, 00001000, 00011000, 10001000

So, the actual strings that contain 3 consecutive 0's is 112-5 = 107.

If we also calculate the number of strings with 4 consecutive 1's, we will have: 16 + 8 + 8 + 8 + 8 = 48.

Therefore, there are 8 strings that we have double counted and they are: 11110000, 11110001, 11111000, 01111000, 00011110, 00011111, 00001111, 10001111.

So, for our final answer, the total number of bit strings of length 8 that contain either three consecutive 0's or four consecutive 1's is 107 + 48 - 8= 147.

7 0

3 years ago

Rational equations help.

omeli [17]

Answer: first option

Step-by-step explanation:

Direct variation equation has the following form:

$y=kx$

Where "k" is the constant of variation.

In direct variation when the variable "x" increases, the variable "y" increases by the same factor and when the variable "x" decreases, the variable "y" decreases by the same factor.

Inverse variation equation has the form:

$y=\frac{k}{x}$

Where "k" is the constant of variation.

In inverse variation when the variable "x" increases, the variable "y" decreases by the same factor and when and when the variable "x" decreases, the variable "y" increases by the same factor.

Given the equation:

$r=\frac{l}{pt}$

You can observe that "r" varies directly with "l" and inversely with "p" and "t"

8 0

3 years ago