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2 years ago

Write a word problem using 7 groups. Solve your problem?

1 answer:

8 0

Seven groups waited in line to see a concert. there were 9 people in each group. how many people were there in total?

9x7= 63

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10.25 : -0.5 = 0<br> -20.5<br> 20.5<br> -0.05<br> 0.05

crimeas [40]

Answer:

20.5

Step-by-step explanation:

hope it helps you that is all I could do.

5 0

2 years ago

What is the equation of the line, in point-slope form, that passes through the points (4, 8) and (2,-2)?

Annette [7]

Answer:

y = 5x -12

Step-by-step explanation:

point-slope form:

y - y1 = m(x-x1)

m= slope

m= (y2-y1)/ (x2-x1)

we have (4, 8) and (2,-2)

x1 = 4 y1= 8

x2= 2 y2= -2

m=( -2-8) / (2- 4)

m= -10/ -2

m= 5

so we have:

y - 8 = 5(x-4)

y - 8= 5x -20

y= 5x -20 +8

y = 5x -12

3 0

3 years ago

Timed test

marysya [2.9K]

Answer:

The correct answer should be 5,130

Step-by-step explanation:

the 3 in 513 is in the ones place, if it were ten times greater than 3 that would be 30, or a 3 in the tens place, the 3 in the number 5,130 is in the tens place, making that the correct choice

4 0

2 years ago

A retailer buys a coat in bulk at a unit price of $45. The coat is marked up to 28% to sell in the store. What is the price of t

inessss [21]

The answer is $57.60

(The original price) 45+ 12.60 (28% of 45) = 57.60

6 0

2 years ago

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago