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kenny6666 [7]
2 years ago
6

You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5.2 minutes to set up the ga

me and 7.3 minutes to play each level. You want to find out how many levels you can play for free.
Mathematics
2 answers:
Marizza181 [45]2 years ago
6 0

Solution:

<u>Note that:</u>

  • 1 game played = 5.2 + 7.3 minutes
  • Trial lasting = 60 minutes

<u>Finding how much levels for free.</u>

  • x games = 5.2 + 7.3x = 60 minutes
  • => 7.3x = 54.8 minutes
  • => x ≈ 7.51

<u>Round it down to find the exact number of free levels you can play.</u>

  • => 7 games

We can play 7 levels for free.

topjm [15]2 years ago
3 0

Answer:

7 levels

Step-by-step explanation:

Let x = number of levels

⇒ 5.2 + 7.3x = 60

⇒ 7.3x = 60 - 5.2 = 54.8

⇒ x = 54.8 ÷ 7.3 = 7.5068...

Need to round down to whole complete levels, so number of levels you can play for free = 7

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C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
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Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

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Five angles are set at a point. The measurement of each angle is one of five consecutive whole numbers. Set up and solve the equ
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Step-by-step explanation:

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3 years ago
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Answer:

Option (C)

Step-by-step explanation:

In the given circle, AB is a chord passing through the center O.

Therefore,chord AB is a diameter of the circle and OC is the radius.

AO = OB = OC

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By applying Pythagoras theorem in right ΔBOC,

BC² = OC² + OB²

BC = \sqrt{OC^{2}+OB^{2}}

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