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prisoha [69]
3 years ago
10

Write an equation of a line, in slope-intercept form, that is perpendicular to the line y=2x+5 and passes through the point (8,-

3)
Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

22

Step-by-step explanation:

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What is the answer for 10-6(5-2y)
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Answer:

-20 + 12y

Step-by-step explanation:

Equation: 10 - 6(5 - 2y)

Step 1:

10 - 30 + 12y          Multiply (5 - 2y) by -6 (distributive property)

Step 2:

-20 + 12y            Subtract 10 by 30 (10 - 30 = -20)

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What is the slope of the line that passes through (-5,-2) and ( 7, -2)
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。☆✼★ ━━━━━━━━━━━━━━  ☾  

slope = difference in y / difference in x

Sub the values in:

slope = (-2- -2) / (7 - -5)

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The slope is 0.

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Which of the following values are solutions to the inequality 1 + 5x < 4?
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Step-by-step explanation:

you cant add 1 to 5x, so subtract 1 on both sides leaving you with 1 + 5x < 4 that equals 5x < 3 -1 -1

then divide 5 from both sides 5x < 3 This leaves 5 5

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Write the first trigonometric function in terms of the second for θ in the given quadrant.
Vinvika [58]
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costheta is only positive in quad4
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