Answer:
Step-by-step explanation:
t=(-2.74 + sqrt(2.74^(2)-4*-4.9*(-10))) / -2*-4.9
t=(-2.74 + sqrt(7.5076-4*+49))/9.8
t=(-2.74 + sqrt(7.5076+45))/9.8
t=(-2.74 + sqrt(52.5076))/9.8
t=(-2.74/9.8)+(sqrt(52.5076))/9.8
this is simplest form, next will be rounded answers
t=0.45981763305
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer:
Step-by-step explanation:
∵ ABCD is a rhombus
∴ AC is ⊥ on BD
∴ ΔAEB is right angled triangle
To make it simple make them all the same fraction
6/24 to trim 4/24 to style and she wants to work for 80/24 hours for 5 days
if each appointment she wants to take 6/24 to trim and 4/24 to style then every appointment will take 10/24 of an hour.
she wants to do 80/24 so she can do 8 appointments a day if each take 10/24
8 appointments a day 5 days a week
8x5= 40
