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If and
, then you can replace
in either equation with the equivalent expression given by the other equation. In this case, you have
and you can solve for .
Then .
For the second system, you can write
Then substitute this into the second equation and you get
so that
Floor(0) -3 = -3 . . . . . only the left-side graphs have this point
floor(0.1) -3 = -3 . . . . only the lower-left graph has this point.
The lower-left selection is appropriate.
floor(0.1) -3 = -3 . . . . only the lower-left graph has this point.
The lower-left selection is appropriate.