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3 years ago

How do you find area for an irregular polygon

Mathematics

2 answers:

Phoenix [80]3 years ago

6 0

Split it into two regular shapes, find each one, and add the areas together.

lubasha [3.4K]3 years ago

3 0

You don't do it it is impossible to do

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Which two numbers add up to 5 and multiply to -84

11111nata11111 [884]

The answer is 12 and -7.

12 * -7 = 84

12 + -7 = 5

5 0

3 years ago

What number am I?

Katyanochek1 [597]

Answer:

The numbers less that 40 which have sum of digits 8 are 17, 26, 35.

Only one of those that has a factor of 7. And that is 35.

So you are 35.

Second way:

The numbers less that 40 which have a factor of 7 are 7,14,21,28,35

Only one of those which has sum of digits as 8. And that is 35.

So you are 35.

Step-by-step explanation:

3 0

2 years ago

What is 50% off $55.oo?

AnnZ [28]

50% of $55 = $27.50

Hope This Helps You!
Good Luck Studying :)

6 0

3 years ago

10n^{2} - 12 = -8<br> Please help

torisob [31]

The value for n is $\frac{\sqrt{10} }{5}$

<h3>solving for n</h3>

<u>given data</u>

10n^{2} - 12 = -8

making n the subject of the formula

10n^{2} = -8 + 12

10n^{2} = 4

divide through by 10

n^{2} = 4 / 10

finding the square root of both sides

n = square root ( 4 / 10 )

$n = \sqrt{\frac{4}{10}$

n = 0.632 or $\frac{\sqrt{10} }{5}$

Read more the subject of formula here: brainly.com/question/21140562

#SPJ1

7 0

1 year ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

3 years ago