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QveST [7]
3 years ago
10

La solución a la ecuación 3x-12=5(x-2) es

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

x=-1

Step-by-step explanation:

3x−12=5(x−2)

3x+−12=(5)(x)+(5)(−2)(Distribute)

3x+−12=5x+−10

3x−12=5x−10

Step 2: Subtract 5x from both sides.

3x−12−5x=5x−10−5x

−2x−12=−10

Step 3: Add 12 to both sides.

−2x−12+12=−10+12

−2x=2

Step 4: Divide both sides by -2.

\frac{-2x}{-2}=\frac{2}{-2} }

x=-1

espero que esto ayude :)

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Help me with this problem
ryzh [129]

Answer:

Looking at the given points we know that it is going to be a triangle because it only have 3 points.  Therefore the figure is a triangle and the area formula would be A=\frac{1}{2}*b*h.

You can look at the attached graph and what we see is that our height of the triangle is from y=-3 to y=4 which means that our height is 7 units high.  We can also see that our base starts at x=-4 and ends at x=4 making us have a base of 8 units.

<u>We then plug in the values and solve</u>

A = \frac{1}{2}*7\ units * 8\ units

A = \frac{1}{2}*56\ units^2

A = 28\ units^2

Therefore, the area of our triangle is 28\ units^2

Hope this helps!  Let me know if you have any questions

4 0
2 years ago
Which will result in a difference of squares? (–7x + 4)(–7x + 4) (–7x + 4)(4 – 7x) (–7x + 4)(–7x – 4) (–7x + 4)(7x – 4)
maw [93]

You can simply expand each product and see whether it gives you a difference of squares.


•  \mathsf{(-7x+4)\cdot (-7x+4)}

That's actually  \mathsf{(-7x+4)^2:}

     \mathsf{(-7x+4)^2}\\\\ \mathsf{=(-7x+4)\cdot (-7x+4)}\\\\ \mathsf{=(-7x+4)\cdot (-7x)+(-7x+4)\cdot 4}\\\\ \mathsf{=49x^2-28x-28x+16}

     \mathsf{=49x^2-56x+16}        <span>✖

which is not a difference of squares.

</span>————<span>—

</span>•  \mathsf{(-7x+4)\cdot (4-7x)}

     \mathsf{=(-7x+4)\cdot 4-(-7x+4)\cdot 7x}\\\\ \mathsf{=-28x+16-(-49x^2+28x)}\\\\ \mathsf{=-28x+16+49x^2-28x}

     \mathsf{=49x^2-56x+16}        ✖

which is not a difference of squares.

—————

•  \mathsf{(-7x+4)\cdot (-7x-4)}

     \mathsf{=(-7x+4)\cdot (-7x)-(-7x+4)\cdot 4}\\\\ \mathsf{=49x^2-28x-(-28x+16)}\\\\ \mathsf{=49x^2-\diagup\!\!\!\!\! 28x+\diagup\!\!\!\!\! 28x-16}\\\\ \mathsf{=49x^2-16}

     \mathsf{=(7x)^2-4^2}        <span>✔

That is a difference of two squares.

</span>————<span>—

</span>•  \mathsf{(-7x+4)\cdot (7x-4)}

     \mathsf{=(-7x+4)\cdot 7x-(-7x+4)\cdot 4)}\\\\ \mathsf{=-49x^2+28x-(-28x+16)}\\\\ \mathsf{=-49x^2+28x+28x-16}

     \mathsf{=-49x^2+56x-16}        <span>✖

</span>which is not a difference of squares.

—————

Only the  third option  will result in a difference of squares.


Answer:  (− 7x + 4) · (− 7x − 4).


I hope this helps. =)

8 0
3 years ago
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410 is 82% of what number
Andrej [43]
Your answer is 500
..............
...........
..........
8 0
2 years ago
Which point is on the graph of f(x)=6x?
Marianna [84]
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4 0
3 years ago
Read 2 more answers
O A box contains 40 oranges, 12 of which are
konstantin123 [22]

Step-by-step explanation:

Nø of sample space, n(s) = 40

nø of unripe oranges, n (u) = 12

no of ripe oranges, n (r) = 40 - 12 = 28

Now

The probability that it is ripe is, P(E)

= n(r) / n(s)

= 28 / 40

= 7 / 10

Also the probability that it is unripe is, P(E)

= n(u) / n(s)

= 12 / 40

= 3 / 10

Hope it will help :)❤

5 0
2 years ago
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