Answer:
y = mx + b, so
y = -0.53x + 1.5
Step-by-step explanation:
1. Find the slope of the line. In his case, then the slope is
, which converts to 0.53
2. Start part of the equation. y = -0.53 x
3. Find the y-intercept of the line. In this case, it is 1.5
4. Now, you can finish your equation. y = -0.53x + 1.5
Answer:
k10.00
Step-by-step explanation:
In the absence of appropriate information regarding the population to which these wages apply, we assume you just want the average of the three numbers:
(7.80 +8.30 +13.90)/3 = 30.00/3 = 10.00
The average of these three rates of pay is k10.00 per hour.
Answer:
Option (C)
Step-by-step explanation:
Since angle 'a' is the inscribed angle of the given triangle
Therefore, angle measure of the intercepted arc will be equal to the double of the inscribed angle.
x = 2a ⇒ a = ![\frac{x}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D)
By the tangent-chord theorem,
"Angle between a chord and tangent measure the half of the angle measure of intercepted minor arc"
= 40°
Therefore, a =
= 40°
Option (C) will be the answer.
Answer:
![0.625kg](https://tex.z-dn.net/?f=0.625kg)
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
![\displaystyle f(t) = a {0.5}^{t/T}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20f%28t%29%20%3D%20a%20%7B0.5%7D%5E%7Bt%2FT%7D%20)
where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
![\displaystyle f(420)=5\cdot{0.5}^{420/140}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28420%29%3D5%5Ccdot%7B0.5%7D%5E%7B420%2F140%7D)
reduce fraction:
![\displaystyle f(420)=5\cdot{0.5}^{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28420%29%3D5%5Ccdot%7B0.5%7D%5E%7B3%7D)
By using calculator we acquire:
![\displaystyle f(420)=0.625](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28420%29%3D0.625)
hence, the remaining sample after 420 days is 0.625 kg