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sattari [20]
3 years ago
6

A series of two-point crosses, involving 7 genes (a-g), were carried out, and the following recombination frequencies were obtai

ned. Place the seven genes into linkage groups (where a linkage group is any group of genes that are genetically linked to each other). Within each linkage group, determine the order of genes and the distances between them.
Genes % recombination Genes % recombination
a-b 50 c-d 50
a-c 50 c-e 26
a-d 12 c-f 50
a-e 50 c-g 50
a-f 50 d-e 50
a-g 4 d-f 50
b-c 10 d-g 8
b-d 50 e-f 50
b-e 18 e-g 50
b-f 50 f-g 50
b-g 50
Biology
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Explanation:

Genes with recombination frequencies(RF) of 50 assort independently and are not genetically links together but gene that have less than 50 RF are genetically linked.

The Linked genes included

a-d 12 c-e 26

a-g 4 d-g 8

b-c 10

b-e 18

Starting the order from the most tightly linked to the least

a-g 4, genetic distance is 4cM

d-g 8 genetic distance is 8cM

b-c 10 genetic distance is 10cM

a-d 12 genetic distance is 12cM

b-e 18 genetic distance is 18cM

c-e 26 genetic distance is 26cM

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Explanation:

Lets break down this question to make the answer easier:

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