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Allushta [10]
3 years ago
6

White rabbits blend in with the snow. Brown rabbits are more likely to be eaten by predators. Is the population of rabbits in ge

netic equilibrium? Explain your answer
Biology
1 answer:
Sergio [31]3 years ago
4 0

Answer:

Yes, the population of rabbits is in genetic equilibrium because both white and brown rabbits have equal chances of survival throughout the year. During the winter season, the brown rabbits stand out and are likely to be eaten by predators, but during the summer, white rabbits stand out and are likely to be eaten.

Explanation:

Brainliest would be appreciated!

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There are two events,
A: the selection belongs to the specific species, or
A' : the selection does not belong to the specific species.
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help plzzz 2 more will mark brainlest. Changes to abiotic factors in an environment can impact biotic factors. Climate change ma
Sedaia [141]

Answer: Here are three reasons if they don't help just tell me.

1. Changes in water temperature can affect the environments where fish, shellfish, and other marine species live. As climate change causes the oceans to become warmer year-round, populations of some species may adapt by shifting toward cooler areas. Oceans are becoming more acidic. 2.  Oceans are becoming more acidic. The acidity of seawater is increasing as a direct result of increasing carbon dioxide levels in the air from human activities, like burning fossil fuels. Concentrations of carbon dioxide are higher than in the last 800,000 years. Carbon dioxide dissolves in water, changing seawater chemistry and decreasing pH (making seawater more acidic). The ocean’s increased acidity results in thinner shells and more shellfish die as they become easier for predators to eat. 3.  More severe storms and precipitation can pollute coastal waters. Warmer oceans increase the amount of water that evaporates into the air. When more moisture-laden air moves over land or converges into a storm system, it can produce more intense precipitation—for example, heavier rainstorms. Heavy rain in coastal areas can lead to increases in runoff and flooding, impairing water quality as pollutants on land wash into water bodies. Some coastal areas, such as the Gulf of Mexico and the Chesapeake Bay, are already experiencing “dead zones” – areas where water is depleted of oxygen because of pollution from agricultural fertilizers, delivered by runoff. The phrase “dead zone” comes from the lack of life – including fish – in these waters.

5 0
3 years ago
During the development of a multicellular organism, its cells specialise. What is this process of specialisation called?
Tomtit [17]
Cellular differentiation 
4 0
2 years ago
Read 2 more answers
When Surita sees a man walking around the shopping mall in December and notices that he is very robust, has a long white beard,
laiz [17]

Answer:

The answer is letter A. automatic

Explanation:

When Surita sees a man walking around the shopping mall in December and notices that he is very robust, has a long white beard, and wears thin rimmed eyeglasses, she immediately assumes that he is a Santa Claus actor taking a break; she is engaging in a(n) __AUTOMATIC_______ process.

5 0
2 years ago
In a population of Mendel's garden peas, the frequency of the dominant A (yellow flower) allele is 80%. Let p represent the freq
DENIUS [597]

Answer:

If the frequency of the dominant allele in the pea population is 0.8, the genotype frequencies in the population would be 0.64 AA, 0.32 Aa, and 0.04 aa.

Explanation:

Hardy-Weinberg equation tells us that:

p2 + 2pq + q2

p2 is the frequency of AA plants

2pq is the frequency of Aa plants, and

q2 the frequency of aa individuals.

A allele in the population is 80%, the frequency is 0.8.

p represent the frequency of A allele. p is 0.8

Therefore calculating for q ( frequency of a allele).

p + q = 1.0

q = 1.0 − p

q = 1.0 − 0.8

q = 0.2

p = 0.8, q = 0.2.

Now we can calculate the predicted frequencies of the different genotypes, remembering that p2 is the frequency of the AA genotype, 2pq is the frequency of the Aa genotype, and q2 the frequency of aa genotype.

p2 = 0.8 x 0.8 = 0.64

2pq = 2 x 0.8 x 0.2 = 0.32

q2 = 0.2 x 0.2 = 0.04.

Thus, we would expect to see genotype frequencies of 0.64 AA, 0.32 Aa, and 0.04 aa in the pea plants.

6 0
3 years ago
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