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2 years ago

15

Coach Thomas has a player who made 9 free throw shots out of 15 in tryouts.To make a team,a player must be able to shoot 65% of

the free throws.Will this player make a team?

1 answer:

Daniel [21]2 years ago

5 0

Answer:

The player will not make the team.

Step-by-step explanation:

To find the percentage he is shooting, divide the number he has made by the number he has taken.

9/15 = 60%

60% is less than the needed 65%

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A similar follow-up study is done on a sample of 25 meat-lovers who never eat vegetables, again randomly selected from the same

Alona [7]

Answer:

The lower limit is 75.04

The upper limit is 78.96

Step-by-step explanation:

From the question we are told that

The sample size is $n = 25$

The sample mean is $\= x = 77$

The standard deviation is $\sigma = 5$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 0.05$

The critical value for $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96* \frac{5 }{\sqrt{25} }$

=> $E = 1.96$

The 95% confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

=> $77 - 1.96 < \mu < 77 + 1.96$

=> $75.04 < \mu < 78.96$

7 0

2 years ago

If an integer n has three unique prime divisors, then it follows that the largest prime divisor of n is less than or equal to cu

TiliK225 [7]

Answer:

False

Step-by-step explanation:

Lets call the three prime divisors of n p, q, and r, being r the largest, we know:

$n=q * p * r$

Now, if

$q * p < r$

then

$n < r * r = r^2$

So:

$\sqrt{n} < \sqrt{r^2} = r$

Also, for every natural greater than one, we know:

$\sqrt[3]{n}$

so

$\sqrt[3]{n}$

from which:

$\sqrt[3]{n} < r$

So, we see, this means the preposition is false, we can find a particular counterexample:

q=2

p=3

p*q = 6

We need to choose a prime greater than 6

r=7

n= 2 * 3 *7 = 42

$\sqrt[3]{42} = 3.4760 < 7$

4 0

3 years ago

PLEASE HELP, I WILL MARK BRANLIEST AND THANKS!!!

Sergeeva-Olga [200]

Step-by-step explanation:

hope it helps you

i think your question was this only

4 0

2 years ago

3. The average distance from the sun to the planet Jupiter is about 483,800.000. The average

MArishka [77]

Answer:

The answer to your question is:

a) sun to jupiter = 4.838 x 10 ⁸ miles

sun to earth = 9.296 x 10 ⁷ miles

b) 5.2 times

Step-by-step explanation:

distance sun to jupiter = 483 800 000 miles

distance sun to earth = 92 960 000 miles

a)

sun to jupiter = 4.838 x 10 ⁸ miles just move the decimal point eight places to the left.

sun to earth = 9.296 x 10 ⁷ miles just move the decimal point seven places to the left.

b)

divide distance sun to jupiter by distance sun to earth =

= 4.838 x 10 ⁸ / 9.296 x 10 ⁷

First divide 4.838 by 9.296 or 4.838 / 9.296 = 0.52

Then we substract the powers: 8 minus 7 or 8 -7 = 1

So we get 0.52 x 10¹ or 0.52 x 10 = 5.2 times

5 0

2 years ago

Two sides of a triangle are two consecutive number, whose area is 17.5cm². Find the numbers

AveGali [126]

Answer:

The numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.

Step-by-step explanation:

Two numbers are consecutives, when their difference is equal to 1. The area of the triangle is determined by the following formula:

$A = \frac{1}{2}\cdot n \cdot (n+1)$

$A = \frac{1}{2}\cdot (n^{2}+n)$

$A = \frac{n^{2}}{2}+\frac{n}{2}$

$n^{2}+n = 2\cdot A$

Where $n$ is the shortest length of the triangle, measured in centimeters.

And we get the following second-order polynomial:

$n^{2}+n -2\cdot A = 0$ (1)

If we know that $A = 17.5\,cm^{2}$ , then the shortest length of the triangle is:

$n_{1} = 5.437\,cm$ and $n_{2} \approx -6.437\,cm$

Since length is a positive variable, the only possible solution is:

$n\approx 5.437\,cm$

Then, the numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.

6 0

2 years ago