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ira [324]
3 years ago
6

Two cards are chosen at random without replacement what is the probability of getting two aces

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
4/52 chance of getting an ace.
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Please solve -3x+12=48
choli [55]

Answer:

x = 12

Step-by-step explanation:

-3x+12=48

      -12 -12

*subtract 12 from both sides

-3x = 36

-3x/3 = 36/3

*divide 3 from each sides

x = 12

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Which property is used in the first step to solve this equation?
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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
avanturin [10]
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900

There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
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Then
.. a = 35 -15 = 20

The price of an advance ticket was 20.
The price of a same-day ticket was 15.
6 0
3 years ago
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