Answer:
eleven below zero
Step-by-step explanation:
opposite of -11 =11 so that doesn't work
positive eleven=11 so that doesn't work
eleven greater than zero=11 so that doesn't work
eleven below zer0= -11 so it works
Answer:
b= 0.9
Step-by-step explanation:
first you find angle B: 180-90-25=65
then you will do law of sine- sin A/a=sin B/b=sin C/c
sin(90)/1=sin 65/b
sin(90)*b=sin(65)*1
sin(90)*b=0.9
b=0.9/sin(90)
b= 0.9
This problem is better understood with a given figure. Assuming
that the flight is in a perfect northwest direction such that the angle is 45°,
therefore I believe I have the correct figure to simulate the situation (see
attached).
Now we are asked to find for the value of the hypotenuse
(flight speed) given the angle and the side opposite to the angle. In this
case, we use the sin function:
sin θ = opposite side / hypotenuse
sin 45 = 68 miles per hr / flight
flight = 68 miles per hr / sin 45
<span>flight = 96.17 miles per hr</span>
Answer: -9°F
Step-by-step explanation:
From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.
The temperature, in degrees Fahrenheit, at noon would be:
= -12°F + 1/2(6)
= -12°F + 3°F
= -9°F
D
Remember starts at zero slope is up 4 right 1
Y= 4/1x+0
Y=4x