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Dovator [93]
3 years ago
8

I’m really struggling with these proofs. We just started learning them and I’m highly confused!! Please help :)

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0
I'm not sure about what exactly your teacher is looking for, but the actual congruency conjecture you would use is:

(angle symbol) 1 (congruency symbol) (angle symbol) 8 - Because they are alternate exterior angles

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√9 is __________ number *
Lera25 [3.4K]

Answer:

√9 is ____rational______ number *

Step-by-step explanation:

√9 = √(3×3)=3 which is rational

7 0
2 years ago
Peter and sai were buying presents. Their parents had given them each an allowance of $7 per week. Each of them saved their mone
Lady bird [3.3K]
They each have $42 because 7 times 6 is 42 and combined they have $84 because 42 + 42=84. 
6 0
3 years ago
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Find the product.<br><br> (-5a ^2)^3·a ^5<br><br> A)-15a10<br> B)-125a11<br> C)15a6<br> D)-125a10
Ber [7]

Answer:

  B)  -125a^11

Step-by-step explanation:

(-5a^2)^3·a^5 = (-5)^3·a^6·a^5

  = (-5)^3·a^(2·3)·a^5

  = (-5)^3·a^6·a^5

  = -125·a^(6+5)

  = -125·a^11 . . . . matches choice B

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

5 0
2 years ago
Read 2 more answers
7x+8(x+1/4)=3(6x-9)-8 need a solution for this problem
valentina_108 [34]
7x+8(x+1/4) = 3(6x-9)-8
7x+8x+2      = 18x - 27 -24
15x + 2        =  18x - 51
       +51                        + 51
15x + 53      = 18x
-15x             = -15x
          53       = 3x
          17.66  = x
5 0
3 years ago
A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, wha
lesantik [10]

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

8 0
3 years ago
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