The volume of the shape is 6 cubic units
<h3>How to determine the volume of the shape?</h3>
<u>Method 1</u>
From the figure, we can see that:
- There are 6 cubes in the figure
- The dimensions of the cubes are equal
- The volume of each cube is 1 cubic unit
So, the volume of the shape is
Volume = Number of cubes * Volume of each cube
Substitute the known values in the above equation
Volume = 6 * 1
Evaluate
Volume = 6
<u>Method 2</u>
From the figure, we can see that:
- There are 6 cubes in the figure
- 2 cubes at the top and 4 at the bottom
- The dimensions of the cubes are equal
- The volume of each cube is 1 cubic unit
So, the volume of the shape is
Volume = Top cubes + Bottom cubes
This gives
Volume = 2 * Volume of each cube + 4 * Volume of each cube
Substitute the known values in the above equation
Volume = 2 * 1 + 4 * 1
Evaluate
Volume = 6
Hence, the volume of the shape is 6 cubic units
Read more about volumes at:
brainly.com/question/1972490
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2(8-4)2-10/2, 8 - 4 is 4 so then times that by 2 and you'll get 8 then multiply that by 2 to get 16, after that you need to subtract it by ten which is 6 then divide it by 2 to get 3.
Hope this helped
600×3.5%=21. As a result, there are 21 phones that likely to be defective. Hope it help!
Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35
From the data, we can say the following:
Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43
Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37
Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.
Answer: D
