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My name is Ann [436]
3 years ago
12

Please help ASAP I really need help please will name you the brain

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

I believe answer B

Step-by-step explanation:

It says shifted UP 3 units and 2+3=5 so that is my answer. Feel free to yell at me if I am wrong.

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Which statement best describes the relationship between the number of chores completed and the number of hours spent on the inte
Maksim231197 [3]
C. For every decrease of one chore completed, one hour was spent on the internet.
4 0
2 years ago
3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
60=F(15) <br><br> Please solve this and show work, please
Lubov Fominskaja [6]

Answer:

f = 4

Step-by-step explanation:

60= 15f

divide both side by 15

f = 4

3 0
3 years ago
Really need an answer to this please help.
Alex

Answer:

a

Step-by-step explanation:

\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}

7 0
3 years ago
What is 0.0592 in scientific notation
DiKsa [7]

Answer:

5.92 times 10 to the 2nd power.

Step-by-step explanation:

So funny I just finished my unit on scientific notation! So what you do is you count the distance from the first non-zero number (in this case, it would be after 5), and count how many places there are until the decimal point. I hope this helped! :D

7 0
3 years ago
Read 2 more answers
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