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3 years ago

What will be the cost of painting a wall of length 32 and breadth 18 m at the rate of AED 50 per sqm

Mathematics

2 answers:

Colt1911 [192]3 years ago

7 0

Answer:total area

32 multiply by 18=576

Then to get the cost of painting you divide 576/50=11.32

Answer 11.32

Step-by-step explanation:

NikAS [45]3 years ago

4 0

Answer:

The cost of painting will be AED 28800

Step-by-step explanation:

First we have to get the area of the wall.

That will be the length multiple by the breadth

Area= 32 x18 = 576 m2

Each m2 cost AED 50

So, the total cost is the area multiple by the cost of each sqm

Cost=576 m2 x AED 50 =28800

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Find the ratio y:x, if 3x=11y,

Aleks [24]

Answer:

3:11

Step-by-step explanation:

3x=11y

Rearrange to the format of the ratio.

11y = 3x

Let's find y/x. y/x is y:x.

11y = 3x

Divide both sides by 11.

11y/11 = 3x/11

y = 3x/11

NOW LET'S DIVIDE BOTH SIDES BY x TO GET x AS THE DENOMINATOR OF y.

y = 3x/11

y/x = (3x/11)/x

y/x = (3x/11) * 1/x

y/x = 3/11

Therefore, y:x = 3:11

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3 years ago

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3 years ago

1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by

Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

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2 years ago

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard devi

kotykmax [81]

Answer:

0.35% of students from this school earn scores that satisfy the admission requirement.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.

This means that $\mu = 1479, \sigma = 302$

The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?

The proportion is 1 subtracted by the pvalue of Z when X = 2294. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2294 - 1479}{302}$

$Z = 2.7$

$Z = 2.7$ has a pvalue of 0.9965

1 - 0.9965 = 0.0035

0.0035*100% = 0.35%

0.35% of students from this school earn scores that satisfy the admission requirement.

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2 years ago