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Taya2010 [7]
2 years ago
11

3x −4 = 11 what is the answer

Mathematics
2 answers:
saul85 [17]2 years ago
7 0

Answer:

x=5

Step-by-step explanation:

denpristay [2]2 years ago
5 0

Answer:

the answer is x=5                              

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1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
Jude puts 6 lemons in bag. If he has 170 lemons how many will be left over
baherus [9]
2 will be left over <span>The largest multiple of </span>6<span> which is less than or equal to </span>170<span> is </span>168
<span>and </span><span>170−168=<span>2</span></span>
7 0
3 years ago
Read 2 more answers
Plz Helppp meeee assapppp
Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = \sqrt{5}

In a right angle triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

For the given triangle,

\cos 45^\circ= \dfrac{x}{\sqrt{5}}

\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}

Multiply both sides by \sqrt{5}.

\dfrac{\sqrt{5}}{\sqrt{2}}= x

\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x

\dfrac{\sqrt{10}}{2}= x

Therefore, the required value of x is \dfrac{\sqrt{10}}{2}.

8 0
2 years ago
Every month, $35 is withdrawal from Tony saving account to pay for his gym membership. He has enough savings to withdraw no more
schepotkina [342]
9 is your answer
because 10times35 is 350 -35 is 315 
3 0
3 years ago
Given the system of equations, what is the y-coordinate of the solution?
bulgar [2K]
If you plug in the second equation (x=5-3/2y) into the first, you get:

5(5-3/2y) - 4y = 7

Simplify:

25 - 15/2y - 4y = 7
-15/2 y - 8/2 y = 7-25 
23/2 y = 18
y = 18 * 2/23 = 36/23

answer B!
6 0
3 years ago
Read 2 more answers
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