Answer:
53 + 3g ≤ 65, g ≤ 4
Step-by-step explanation:
To solve for g:
53 + 3g ≤ 65
First, subtract 53 from both sides.
53 - 53 + 3g ≤ 65 - 53
=> 3g ≤ 12
Divide 3 by both sides
=> 3g / 3 ≤ 12 /3
=> g ≤ 4
Therefore, g ≤ 4
Hope this helps :)
For this case, the first thing we must do is define variables.
We have then:
x: number of checks.
y: total cost.
We now write the linear function that represents the problem.
We have then:

Then, Jerome issues 10 checks in a month.
Therefore, we evaluate the function for x = 10.
We have then:
Answer:
a monthly checking account will cost him about:
y = 12.5 $
It’s the second answer. 2•10•2 + 2•10•3 + 2•2•3
It is 6 was not multiplied by 3
The answer should be 6(m+3)= 6m+ 18
What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.

so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2