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3 years ago

The distance between (0,-4) and (2,-5)

Mathematics

1 answer:

alex41 [277]3 years ago

8 0

Step-by-step explanation:

d= $\sqrt{ (0-2)^2 + (-4-(-5))^2}$

d= $\sqrt{(-2)^2 + (1)^2}$

d= $\sqrt{4 + 1}$

d= $\sqrt{5}$

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Simplify 12 to the 3rd over 12 to the 7th.

Ganezh [65]

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The 2nd choice is appropriate.

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3 years ago

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Triangle ABC has been reflected over the y- axis to create triangle A’B’C’. Which of the following statements is true ? B’C’ = 2

Klio2033 [76]

Answer:

B'C' = 2

Step-by-step explanation:

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3 years ago

Box A is 12 inches by 18 inches by 24 inches. Box B is 12 inches by 12 inches by 30 inches. In cubic inches, how much greater is

Burka [1]

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Box A's volume is bigger by 864 cubic inches

Step-by-step explanation:

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find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS

charle [14.2K]

Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

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3 years ago

Frequency (y) varies inversely with wavelength (x). Find the frequency (measured in THz ) of blue light if its k value is 175,72

horsena [70]

We have been that frequency (y) varies inversely with wavelength (x).

We know that two inversely proportional quantities are in form $a=\frac{k}{b}$ , where a is inversely proportional to b and k is constant of variation.

Our required equation would be $y=\frac{k}{x}$ .

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$y=\frac{175,720}{230}$

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3 years ago

The distance between (0,-4) and (2,-5)​

The distance between (0,-4) and (2,-5)