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natali 33 [55]
3 years ago
14

The distance between (0,-4) and (2,-5)​

Mathematics
1 answer:
alex41 [277]3 years ago
8 0

Step-by-step explanation:

d=\sqrt{ (0-2)^2 + (-4-(-5))^2}

d= \sqrt{(-2)^2 + (1)^2}

d=\sqrt{4 + 1}

d= \sqrt{5}

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Answer:

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Step-by-step explanation:

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This is urgent, please answer!
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I think its C) bc you would take 3.14 x4= 12.56
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Simplify 571-12311-2011. (1 point)<br> 0 -33-19<br> L<br> -1119<br> O-9/11<br> -9 33
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a-plus auto body is painting desings on a customer's car. they had 18 pints of blue paint on hand. they used 1/2 of it for the f
netineya [11]

4³/₄ pints

<h3>Further explanation</h3>

<u>Given:</u>

A-Plus auto body is painting desigs on a customer's car.

  • They had 18 pints of blue paint on hand.
  • They used \frac{1}{2} of it for the flames, and \frac{1}{3} of it for the sparks.
  • They needed 7\frac{3}{4} pints of blue paint to paint the next design.

<u>Question:</u>

How many more pints of blue paint will they need?

<u>The Process:</u>

From the denominators 2 and 3 above, we get LCM = 6.

Let us draw a diagram that contains all the pints.

18 \ pints \div 6 \ units = 3 \rightarrow \boxed{3}\boxed{3}\boxed{3}\boxed{3}\boxed{3}\boxed{3} = 18 \ pints

The flames: \frac{1}{2} or half of 6 unit above, that is \boxed{3}\boxed{3}\boxed{3} = 9 \ pints

The sparks: \frac{1}{3} = \frac{2}{6} or 2 of 6 unit above, that is \boxed{3}\boxed{3} = 6 \ pints

So, the remainder is 18 - 9 - 6 = 3 pints.

They needed 7\frac{3}{4} pints of blue paint to paint the next design.

Let us count how many more pints of blue paint will they need.

\boxed{7\frac{3}{4} - 3 = ?}

\boxed{= \bigg( 7 + \frac{3}{4} \bigg) - 3}

\boxed{= 7 - 3 + \frac{3}{4}}

\boxed{\boxed{ \ 4\frac{3}{4}}}

Thus, they 4\frac{3}{4} pints more of blue paint.

<h3>Learn more</h3>
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Keywords: A-Plus, auto body, painting, designs, on a customer's car, they had 18 pints, blue paint, 1/2, for the flames, 1/3, the sparks, they needed, 7³/₄, the next design, how many more, will they need

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What is the range of the data set?<br> 62 44 31 31 12 89 71
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The data range is: 89 - 12 = 77. So the Range is 77.

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