Question

The point (5/13, y) in the fourth quadrant corresponds to angle theta on the unit circle. Find sec theta and cot theta

Answer 1

Cos (theta) =$\frac{5}{13}$ sec (theta) = $\frac{1}{cos(theta)} = \frac{1}{ \frac{5}{13} }= \frac{13}{5}$ sin(theta)=$\sqrt{1- cos^{2}(theta) } = \sqrt{1 - \frac{25}{169} } = \sqrt{ \frac{144}{169} }=- \frac{12}{13}$ cot(theta)=$\frac{cos(theta)}{sin(theta}= \frac{ \frac{5}{13} }{ \frac{-12}{13} }= \frac{-5}{12}$