2 years ago

Find all solutions of e^(e^z)=1

1 answer:

8 0

Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?

You might be interested in

Which expression represents 10 in rational exponent form?

SSSSS [86.1K]

The correct answer is C

5 0

3 years ago

Kenny wrote the equation for a linear relationship shown below

Ilia_Sergeevich [38]

Y would equal -17! Good luck!

4 0

3 years ago

Read 2 more answers

Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col

natali 33 [55]

Answer:

$\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

$\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]$