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jonny [76]
4 years ago
5

Complete the factorization of 3x2 – 5x + 2.

Mathematics
2 answers:
Ad libitum [116K]4 years ago
8 0
Multiply the first coefficient (3) and the last term (2) to get 3*2 = 6

We need to find two numbers that

a) multiply to 6
AND
b) add to -5 (middle coefficient)

Such two numbers are -3 and -2
-3 times -2 = 6
-3 plus -2 = -5

So we can break up the -5x into -3x-2x and then factor by grouping

--------------

3x^2-5x+2

3x^2-3x-2x+2

(3x^2-3x)+(-2x+2)

3x(x-1)+(-2x+2)

3x(x-1)-2(x-1)

(3x-2)(x-1)

So the two factors are (3x-2) and (x-1)

The answers are A and C
Svetlanka [38]4 years ago
4 0

Answer:

It's B and D for anyone else that needs it.

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Answer:

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Step-by-step explanation:

The diagonals of a rhombus are perpendicular to each other, so angles (2) and (3) are equal 90°.

To find angle (1), we can use the sum of internal angles in the left triangle with angles 52°, (1), and (2):

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