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SVETLANKA909090 [29]
3 years ago
12

Elena went to a store where you can scoop your own popcorn and buy as much as you want. She bought 10 ounces of spicy popcorn fo

r $2.50.
Mathematics
1 answer:
kramer3 years ago
6 0

Answer:

1 ounce costs 0.25$

Step-by-step explanation:

I have no idea what the question is as there is no question but that's the answer for what I think you wanted to know

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Answer quick before I fail :)
insens350 [35]

I’m not 100% sure but I think it’s 14/49

5 0
3 years ago
Read 2 more answers
What is the measure of [theta]?
Brums [2.3K]
The answer is D
=  \frac{12}{4}
= 3 \: radians
4 0
4 years ago
Choose any four consecutive even numbers. (For example: 6, 8, 10, 12). Multiply the two middle numbers together. (e.g. 8 x 10 =
Ludmilka [50]

Answer:

Step-by-step explanation:

let the consecutive even numbers be  2n-2,2n,2n+2,2n+4 where n>0 and n is an integer.

2n(2n+2)-(2n-2)(2n+4)

=4n²+4n-(4n²+8n-4n-8)

=4n²+4n-4n²-8n+4n+8

=8

6 0
3 years ago
Opal makes $15 per hour working for a photographer. She also coaches a competitive soccer team for $10 per hour.
Jlenok [28]

The system of inequalities that represents the given situation are x + y ≤ 20 and 15x + 10y ≥ 90.

The parameters needed to model the inequalities;

  • amount made by Opal working for a photographer = $15 per hour
  • amount made in the soccer team = $10 per hour
  • minimum amount Opal needs to make a week = $90
  • maximum number of hours Opal needs to work = 20 hours

Let the number of hours Opal works for a photographer = x

Let the number of hours Opal works in soccer team = y

The first system of inequality in the given situation is represented as;

x + y ≤ 20

The second system of inequality in the given situation is represented as;

15x + 10y ≥ 90

Thus, the system of inequalities that represents the given situation are x + y ≤ 20 and 15x + 10y ≥ 90.

learn more here: brainly.com/question/9774970

7 0
2 years ago
What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1
7nadin3 [17]
Ans: Option (1) <span>Discontinuity at (1, 7), zero at ( negative four thirds , 0) 
</span>
Explanation:
Given function:
f(x) =  \frac{3x^2 + x - 4}{x-1}

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \  ~ x =  \frac{-4}{3} \\ Hence~zeros=(  \frac{-4}{3}, 0)

5 0
3 years ago
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