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Rudiy27
1 year ago
13

Two metal disks, one with radius r = 2. 50 cm and the other with radius r = 5. 00 cm are welded together and

Mathematics
1 answer:
vova2212 [387]1 year ago
4 0

The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.

<h3>What is moment of inertia?</h3>

Moment of inertia is the quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.

Using the formulas to calculate the moment of inertia of a solid cylinder:

I = ½MR²

Where;

I = moment (kgm²)

M = mass of object (Kg)

R = radius of object (m)

Total moment of inertia of the two disks is expressed as: I = I(1) + I(2)

That is;

I = ½M1R1 + ½M2R2

According to the provided information;

R1 = 2.50cm = 0.025m

M1 = 0.800kg

R2 = 5.00cm = 0.05m

M2 = 1.70kg

I = (½ × 0.800 × 0.025²) + (½ × 0.05² × 1.70)

I = (½ × 0.0005) + (½ × 0.00425)

I = (0.00025) + (0.002125)

I = 0.002375

I = 2.375 × 10-³ Kgm²

Hence The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.

To know more about moment of inertia follow

brainly.com/question/14460640

#SPJ4

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S=Selling price 135
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Let quantity be Q
The formula to break even is
135Q-75Q-3300=0
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So the store must sell 50 bicycles to break even

Hope it helps!

6 0
3 years ago
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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
An administrator at a local high school wants to investigate whether there is an association between the grade level of a studen
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Answer:

c.

Step-by-step explanation:

The following is how the p-value should be interpreted:

The probability of getting the test statistics value at least as intense as it might have been acquired during the test, assuming the null hypothesis is true, is considered as the p-value.

Null hypothesis

\mathbf{H_o :} A student's grade level has no bearing or association on how they commute to school.

Alternative hypothesis;

\mathbf{H_1: } There is a link between a student's grade level and the way they get to school.

The test statistic's value is 14.63, and the p-value is 0.2636.

As a result, the p-value is interpreted as that of option c in the question.

5 0
3 years ago
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HELP ASAP!!!! SO STUCK ON THIS! Will give brainliest IF CORRECT! :) please help! Be sure please!
vlada-n [284]
If I can read the #'s correctly:
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so your ratio of haves to have nots is 170 to 160

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4 0
3 years ago
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–q + 23 + 11n + 7j + 20 – 13r<br> What are the coefficient in this expression
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