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8090 [49]
3 years ago
5

The diagram shows a trapezoid prism.

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

Given:

The area of the cross-section is 55cm².

The volume of the prism is 330cm³.

To find:

The length of the prism.​

Solution:

We have,

Area of the cross-section = Area of base = 55 cm²

Volume of the prism = 330cm³.

Let x be the length(height) of the prism.

We know that,

\text{Volume of prism}=\text{Base area}\times height

330=55\times x

\dfrac{330}{55}=x

6=x

Therefore, the length of the prism is 6 cm.

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What is the principal which would amount to $6900 in 3 years at 5% simple interest per annum?​
balu736 [363]

Answer:

$6000

Step-by-step explanation:

accumulated amount = A = PI

A = $6900

Let P = x

6900 - I = x

I = (x)(0.05)(3yrs) = 0.15x

6900 - 0.15x = x

Add

6900 = 1.15x

Divide, solve for x

x = 6000

8 0
3 years ago
Someone please help me with my homework
spin [16.1K]
Answer: 
20700 feet per hour

Explanation: 
Convert 345 feet per minute to 345 feet per hour. 
First find how many minutes are in an hour:
60 minutes = 1 hour. 
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345 feet • 60 = 20700 feet per hour.
3 0
3 years ago
Tell whether each relationship is a function.
Serhud [2]

Answer:

3 is a function.

1 and 2 are not.

Step-by-step explanation:

1 and 2 are not functions because we can draw a vertical line which passes through  more than one point on the graphs.

You cant do this on graph 3 so it is a function.

8 0
3 years ago
An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click
Sergeeva-Olga [200]

Answer:

A.    \mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

B.    \mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

Step-by-step explanation:

Given that:

An investment of  Amount = $8000

earns  at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A)  Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

A = Pe^{rt}

where;

A = (8000) \ e ^{0.7t}

The instantaneous rate of change = \dfrac{dA}{dt}

\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )

= 8000 \dfrac{d}{dt}e^{0.07 \ t}

\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 2 years; the instantaneous rate of change is:

\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}

\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

12000 = (8000)e^{0.07 \ t}

\dfrac{12000 }{8000}= e^{0.07 \ t}

1.5= e^{0.07 \ t}

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 5.79

\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}

\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

7 0
3 years ago
I'll give brainliest!!!
Schach [20]

Answer:

Your answer is C like I said earlier

Step-by-step explanation:

Some person deleted my answer from a couple days ago...

5 0
3 years ago
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