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3 years ago

I WILL GIVE BRAINLIEST!!! PLZ HELP ASAP!!!

Mathematics

2 answers:

Fed [463]3 years ago

7 0

Answer:

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = E(- 2, 2) and (x₂, y₂ ) = F(4, - 6)

EF = $\sqrt{(4+2)^2+(-6-2)^2}$

= $\sqrt{6^2+(-8)^2}$

= $\sqrt{36+64}$

= $\sqrt{100}$ = 10 → C

AnnZ [28]3 years ago

6 0

Answer: C.

Step-by-step explanation: I took this test about 1 day ago and got this

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-9 ( greater less than)<br> (> with a line under it) <br> 2m + 2 - 3

Margaret [11]

Answer:

m is less than or equal to -4

Step-by-step explanation:

8 0

3 years ago

Need help will mark brainliest

Tcecarenko [31]

I think it’s going to be 4/16 but I’m not a math major and I suck at math so I’m not sure

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4 years ago

If a coin is flipped twenty-five times and lands tails up seventeen times, the experimental probability that the coin lands tail

aliina [53]

Tails was landed 17/25 times, so the experimental probability would be .68 or 68%
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Hope this helps!

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3 years ago

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3241004551 [841]

Answer:

i do not know what are your talking about.

Step-by-step explanation:

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3 years ago

Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$

Step-by-step explanation:

You are going to integrate the following function:

$g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}$ (1)

furthermore, you know that:

$\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}$

lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

furthermore you use the fact that:

$I_n=-\frac{\partial I_{n-2}}{\partial a}$

by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

5 0

3 years ago

Read 2 more answers