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3 years ago

What value of x makes this equation true?

Mathematics

2 answers:

natali 33 [55]3 years ago

4 0

Answer:

-1.8 =x

Step-by-step explanation:

12(x+3)=-8x

Distribute

12x +36 = -8x

Subtract 12x from each side

12x-12x +36 = -8x-12x

36 = -20x

Divide each side by -20

36/-20 = -20x/-20

-9/5 = x

Changing to decimal form

-1.8 =x

Svetllana [295]3 years ago

4 0

Answer:

c. -1.8

Step-by-step explanation:

12(x+3) = -8x

12x + 36 = -8x

20x = -36

x = -36/20

x = -1.8

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slava [35]

Answer:

47+ y = 180 (linear pair)

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3 years ago

Help math word problem

erastova [34]

Lets x = # pounds of coffe

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3 years ago

Which is greater than 1/7 or 4/6

Alex Ar [27]

Answer:

4/6

Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

kramer

Answer:

Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

Also ,

$\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}$

And we need to find out the value of A , when

a = 3
b = 4
c = 5

So , on substituting the respective values to find s we have ,

$\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}$

Now let's find out A as ,

$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\$

$\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\$

$\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\$

$\sf\red{\longrightarrow}A = 3*2\\$

$\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}$

7 0

2 years ago

Solve –19 = x – 4. Question 9 options: A) x = –15 B) x = –23 C) x = –76 D) x = 25

AveGali [126]

Answer:

A.) x = -15

Step-by-step explanation:

-19+4 = x

x = -15

4 0

2 years ago