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3 years ago

Help please!!

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

Step-by-step explanation:

Symmetry is when you can flip the figure over a line and it will perfectly match the other side.

We see that if we draw a vertical line down the middle and a horizontal line across the middle, we get mirror images. So that's 2.

Then notice that we can draw two diagonals across the image, one from the upper left corner to the lower right corner and the other from the upper right corner to the lower left corner. That's another 2.

We try to find more, but try as we might, there are no others to be found.

Thus, there are 4 lines of symmetry.

Hope this helps!

mixas84 [53]3 years ago

7 0

Im sure there are like 4

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In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq

MAXImum [283]

<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
P(B) = 20/80 = 1/4 = probability of picking someone taking French
P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

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3 years ago

Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred

Ksivusya [100]

1. $m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}$ , then $m\angle ABC=m\angle ACD$ and triangles ADC and ACB are similar by AAA theorem.

2. The ratio of the corresponding sides of similar triangles is constant, so

$\dfrac{AC}{AB}= \dfrac{AD}{AC}$ .

3. Knowing lengths you could state that $\dfrac{b}{c}= \dfrac{e}{b}$ .

4. This ratio is equivalent to $b^2=ce$ .

5. $m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}$ , then $m\angle BAC=m\angle BCD$ and triangles BDC and BCA are similar by AAA theorem.

6. The ratio of the corresponding sides of similar triangles is constant, so

$\dfrac{BC}{BD}= \dfrac{AB}{BC}$ .

7. Knowing lengths you could state that $\dfrac{a}{d}= \dfrac{c}{a}$ .

8. This ratio is equivalent to $a^2=cd$ .

9. Now add results of parts 4 and 8:

$b^2+a^2=ce+cd$ .

10. c is common factor, then:

$b^2+a^2=c(e+d)$ .

11. Since $e+d=c$ you have $a^2+b^2=c\cdot c=c^2$ .

7 0

3 years ago

Read 2 more answers

For the function f(x)=x^2, what effect will multiplying f(x) by 1/2 have on the graph?

erma4kov [3.2K]

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f ( x ) = a · x²
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Here: a = 1/2 < 1
Answer:
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4 years ago

The slope of the line below is -3. Which of the following is the point-slope

Anna [14]

Given:

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To find:

The point-slope form of the line.

Solution:

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