Answer:
Let's complete the square first.
y = x² + 6x + 3
= (x² + 6x + 9) - 6
= (x + 3)² - 6
Therefore, the vertex is (-3, -6) and since the coefficient of (x + 3)² is positive, the vertex is a minimum.
Answer: (2x+5)(x^2+3)
Step-by-step explanation:
Combine like terms, find greatest common factors, and reduce fractions
Answer:
I cant see the question its very blurry
Step-by-step explanation:
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
