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2 years ago

5

Sarah is making a scale drawing of a painting that is 60 in. wide by 120 in. high. Her paper is 15 in. wide and 25 in. tall. She

decides to use the scale 1 in. = 4 in. Is this a reasonable scale?

1 answer:

Law Incorporation [45]2 years ago

6 0

Answer:

This is not a reasonable scale.

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Can anyone help me with this? i dont understand it, thank you.

valina [46]

Answer:

$3(x + 2) = 2(x + 2) \\ 3x + 6 = 2x + 4 \\ 3x - 2x = 4 - 6 \\ x = - 2$

4 0

2 years ago

Add 77 -10 with its additive inverse.

Ganezh [65]

Answer: 77 - 10 = 67, and the additive inverse of 77 - 10 is 77 + 10. 77 + 10 = 87.

Hope this helps! This question was kind of confusing for me, because I didn’t understand why you said to add 77 - 10… is this is the incorrect answer sorry your question was worded weird

4 0

2 years ago

A space shuttle travels at 2.6 x 10,000 feet per second. An hour is 3.6 x 1,000 seconds. This expression can be used to find the

guapka [62]

Answer:

7.22 feet

Step-by-step explanation:

From the question,

s = d/t................. Equation 1

Where s = speed of the space shuttle, d = distance traveled by the shuttle in an hour, t = time taken to travel the distance

make d the subject of the equation,

d = s×t.................... Equation 2

Given: s = 2.6×10000 feet per seconds, t = 1 hour = 3.6×1000 seconds.

Substitute these values into equation 2

d = (2.6×10000)/(3.6×1000)

d = 26000/3600

d = 7.22 feet.

Hence the shuttle travels 7.22 feet in an hour

6 0

3 years ago

Which one have is the coldest temperature negative numbers or positive numbers

aalyn [17]

Answer:

Step-by-step explanat số âm vì số âm < số dương mà nhiệt đọ càng thấp thì càng lạnhion:

6 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago