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siniylev [52]
2 years ago
9

Round to the nearest hundredth 5.193

Mathematics
2 answers:
GenaCL600 [577]2 years ago
8 0

Answer:

5.19

Step-by-step explanation:

Remember this whenever rounding. If the digit before you are rounding to is less than 5, you ALWAYS round down. If it is 5 or greater, you ALWAYS round up.  

In 5.193,  

5 represents the ones

5.1 represents the ones in the tenths column

5.19 represents the ones in the hundredths column

5.193 represent the ones in the thousandths column

ValentinkaMS [17]2 years ago
4 0
Answer:
5.19

Explanation:

The first place value after the decimal point is called the tenths place. The second place value after the decimal point is called the hundredths place.
To round, remember that you take the place value after the one that it is asking for and numbers 5 and up round up, numbers 4 and below round down.
Hope this helps :)

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If lines and and cd are parallel,which if the following statements are true?
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A

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AB ll CD

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In March, there will be two conferences: one for math and one for history. So far, 7 people have signed up for the math conferen
otez555 [7]

Answer:

After 4 days, the number of people attending both conferences be the same.      

Step-by-step explanation:

We are given the following in the question:

Maths conference:

Number of people already signed = 7

Number of people who sign up each day = 2

Thus, the number of people who will sign up for maths conference in x days will be given by the linear function:

 f(x) = 7+2x

History conference:

Number of people already signed =11

Number of people who sign up each day = 1

Thus, the number of people who will sign up for maths conference in x days will be given by the linear function:

 g(x) =11+x

Both conference will have same number of people when

f(x) = g(x)\\\Rightarrow 7 + 2x = 11+x\\\Rightarrow x = 4

Thus, after 4 days, the number of people attending both conferences be the same.

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3 groups of a number plus 2
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X times x times x +2
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The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
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