Question

F(x)=(x+4)(x-2)(x+4)(x+4) What is the multiple zero? Multiplicity is?

Answer 1

$f(x)=(x+4)(x-2)(x+4)(x+4)\\f(x)=(x+4)^3(x-2)=0\\(x+4)^3=0~|~(x-2)=0\\(x+4)(x+4)(x+4)=0~|~x=2\\x=-4,2$

The multiple zero is x = -4.

The multiplicity is 2 because there are two values of x.