F(x)=(x+4)(x-2)(x+4)(x+4) What is the multiple zero? Multiplicity is?

1 answer:

8 0

$f(x)=(x+4)(x-2)(x+4)(x+4)\\f(x)=(x+4)^3(x-2)=0\\(x+4)^3=0~|~(x-2)=0\\(x+4)(x+4)(x+4)=0~|~x=2\\x=-4,2$

The multiple zero is x = -4.

The multiplicity is 2 because there are two values of x.

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