Cameron has 12 fish.
The denominator in 1/3 tells you that there are THREE equal parts in the whole group. Draw 3 circles to show THREE equal parts.
Since 4 fish are 1/3 of the whole group, draw FOUR counters in the first circle.
Since there are FOUR counters in the first circle, draw FOUR counters in each of the remaining circles. Then find the total number of counters.
So Cameron has TWELVE fish in his tank
Is there a chart because there is no reference..
6x−12+2x=3+8x−15
Simplify:
6x+−12+2x=3+8x+−15
(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)
8x+−12=8x+−12
8x−12=8x−12
Subtract 8x from both sides.
8x−12−8x=8x−12−8x
−12=−12
Add 12 to both sides.
−12+12=−12+12
0=0
The real numbers are the only solution we can have.
S + a = 300...s = 300 - a
8s + 12a = 3200
8(300 - a) + 12a = 3200
2400 - 8a + 12a = 3200
-8a + 12a = 3200 - 2400
4a = 800
a = 800/4
a = 200 <==== 200 adult tickets
s = 300 - a
s = 300 - 200
s = 100 <=== 100 student tickets
Answer:
y-1=-7/2*(x+3)
Step-by-step explanation:
