To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
Answer:
12 hours
Step-by-step explanation:
Full time job:
Earning per week = $475
Part time job :
Earning per hour = $11
Number of working hours per week at per time job to increase weekly earning to atleast $600 ;
Let number of hours = h
Full time earning + earning per hour * (number of hours) ≥ 600
$475 + ($11 * h) ≥ 600
$475 + $11h ≥ 600
11h ≥ 600 - 475
11h ≥ 125
h ≥ 125 / 11
h ≥ 11.36
Hence, sharia will need to work for 12 hours per week
Is there more to the question?
Answer:
17 for 1 point shots and 35 for two point shots.
Step-by-step explanation:
let the number of 1 point shots be x
let the number of 2 point shots be y
x + y = 52 (1)
x + 2y = 87 (2)
subtracting (1) from (2)
y = 35
from (1) x = 52 - y = 52 - 35 = 17
Hence number of 1 pointers = 17
number of 2 point shots = 35
checking; 17 + 35 =52 ; and 17+ 2*35 = 87
Answer:
0.9209
Step-by-step explanation:
The question means what is the probability of not getting 5 three leafed soybeans
To find the probability we can subtract the number of getting 5 three leafed soybeans from 1
1 - 0.6×0.6×0.6×0.6= 0.9209
