Answer:
First choice
Step-by-step explanation:
The discontinuity is removable if by reducing the fraction that discontinuity doesn't continue to exist as a discontinuity.
Example of, (x-1)/(x-1) has a a discontinuity at x=1 and it's removable because the fraction reduces to 1 which doesn't have a discontinuity at x=1.
Example not of, (x-1)/(x-2) has a discontinuity at x=2 and it is not removable because we can't get rid of the x-2 factor in the denominator.
The first choice has a discontinuity at x=-1 and it is removable because x^2-x-2=(x-2)(x+1) and the x+1's will cancel on top and bottom making the point at x=-1 a removable discontinuity.
3(8)-12=12
24-12=12
The fourth choice.
Yeah I think you already got it
If B is the midpoint of AC, then AB=BC. It is also BC=AC-AB
AB = x + 6
AC = 5x - 6
BC = (5x - 6) - (x + 6)
We can kinda use distributive property, like this:
BC = 5x - 6 -x - 6
Combine like terms:
BC = 4x - 12
To verify, we can add AB and BC to see if their sum is equal to AC.
(x + 6) + (4x - 12) = 5x - 6
If we are correct, this equation will be true.
x + 6 + 4x - 12 = 5x - 6
Combine like terms:
6 + 5x - 12 = 5x - 6
5x - 6 = 5x - 6
It's correct!
BC = 4x - 12. Final Answer.
Let me know if you have any questions about this! :)
"the following" of what? I think you are missing the list
Answer:
g(x) = - x² - x + 12
Step-by-step explanation:
Given
g(x) = (- x - 4)(x - 3)
Each term in the second factor is multiplied by each term in the first factor, that is
- x(x - 3) - 4(x - 3) ← distribute both parenthesis
= - x² + 3x - 4x + 12 ← collect like terms
= - x² - x + 12 ← in standard form
