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Luba_88 [7]
3 years ago
10

A certain number line uses 20 spaces between consecutive integers.

Mathematics
1 answer:
noname [10]3 years ago
5 0

Answer:

Distance between two consecutive tick marks is 0.05 units.

Step-by-step explanation:

We are given the following information in the question:

It is given that there are 20 ticks between two consecutive number.

Let n and n+1 be the consecutive number.

Formula:

Distance between two ticks =

\displaystyle\frac{\text{Difeerence between the numbers}}{\text{Number of ticks}}\\\\= \frac{(n+1)-n}{20} = \frac{1}{20} = 0.05

Thus, distance between two consecutive tick marks is 0.05 units.

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If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.
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Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

WX=\sqrt{(-3-(-10))^2+(-1-4)^2}

WX=\sqrt{(-3+10)^2+(-5)^2}

WX=\sqrt{(7)^2+(-5)^2}

WX=\sqrt49+25}

WX=\sqrt{74}

Similarly,

XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}

WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}

Now,

WX=WY

So, triangle is an isosceles triangles.

and,

WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2

WX^2+WY^2=74+74

WX^2+WY^2=148

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WX^2+WY^2=WY^2

So, triangle is right angled triangle.

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